Answer:
Step-by-step explanation:
b/c the function goes thur the point (1,4) we know it's 4 times more than f(x) so g(x) = 4
The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C: [130.10, 143.90]
<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>
Suppose that we have:
- Sample size n > 30
- Sample mean =

- Sample standard deviation = s
- Population standard deviation =

- Level of significance =

Then the confidence interval is obtained as
- Case 1: Population standard deviation is known

- Case 2: Population standard deviation is unknown.

For this case, we're given that:
- Sample size n = 90 > 30
- Sample mean =
= 138 - Sample standard deviation = s = 34
- Level of significance =
= 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).
At this level of significance, the critical value of Z is:
= ±1.645
Thus, we get:
![CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]](https://tex.z-dn.net/?f=CI%20%3D%20%5Coverline%7Bx%7D%20%5Cpm%20Z_%7B%5Calpha%20%2F2%7D%5Cdfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D%5C%5CCI%20%3D%20138%20%5Cpm%201.645%5Ctimes%20%5Cdfrac%7B34%7D%7B%5Csqrt%7B90%7D%7D%5C%5C%5C%5CCI%20%5Capprox%20138%20%5Cpm%205.896%5C%5CCI%20%5Capprox%20%5B138%20-%205.896%2C%20138%20%2B%205.896%5D%5C%5CCI%20%5Capprox%20%5B132.104%2C%20143.896%5D%20%5Capprox%20%5B130.10%2C%20143.90%5D)
Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C: [130.10, 143.90]
Learn more about confidence interval for population mean from large samples here:
brainly.com/question/13770164
Answer:
Step-by-step explanation:
2x - 3y = 9
-3y = -2x + 9

Parallel lines have same slope.So,
Slope m = 2/3
(4 , -1)
Equation: y - y1 = m(x - x1)
![y-[-1]=\frac{2}{3}(x - 4)\\\\y+1=\frac{2}{3}*x - \frac{2}{3}*4\\\\y+1=\frac{2}{3}x-\frac{8}{3}\\\\y=\frac{2}{3}x-\frac{8}{3}-1\\\\y=\frac{2}{3}x-\frac{8}{3}-\frac{3}{3}\\\\y=\frac{2}{3}x-\frac{11}{3}](https://tex.z-dn.net/?f=y-%5B-1%5D%3D%5Cfrac%7B2%7D%7B3%7D%28x%20-%204%29%5C%5C%5C%5Cy%2B1%3D%5Cfrac%7B2%7D%7B3%7D%2Ax%20-%20%5Cfrac%7B2%7D%7B3%7D%2A4%5C%5C%5C%5Cy%2B1%3D%5Cfrac%7B2%7D%7B3%7Dx-%5Cfrac%7B8%7D%7B3%7D%5C%5C%5C%5Cy%3D%5Cfrac%7B2%7D%7B3%7Dx-%5Cfrac%7B8%7D%7B3%7D-1%5C%5C%5C%5Cy%3D%5Cfrac%7B2%7D%7B3%7Dx-%5Cfrac%7B8%7D%7B3%7D-%5Cfrac%7B3%7D%7B3%7D%5C%5C%5C%5Cy%3D%5Cfrac%7B2%7D%7B3%7Dx-%5Cfrac%7B11%7D%7B3%7D)
b = -11/3
<span>Given
situation : 2 improper fraction is multiplied. Now is the product always more
than than 1?
Yes, the product is always more than 1. Because take note that in improper
fraction, the numerator is always higher compare to the denominator of the
given fraction. That means when you divide the numerator from the denominator,
the answer would always be more than 1.
Example:
=> 5 / 4 x 4 / 2
=> 20 / 8 or equals to 5/2
now divide
=> 5 / 2
=> 2 1/2
</span>