Answer:
The angles that are supplementary to angle 7 includes angle 5 and angle 8.
The following solutions to the given system of inequalities shown above would be option c : (-3, -5) option d : (0, 4) option e. (4, 4) and option f. <span>(2, -1)
So how did I know the answer. To check this, you just have to substitute the values.
For example let us take option c (-3, -5)
y </span><span>< 3x + 5
-5 </span><span>< 3(-3) + 5
-5 </span><span>< -9 + 5
-5 </span><span>< -4 <<You see that -4 is greater than -5 which makes this inequality correct. This is the same process as with the other correct options.
Hope that this answer helps.</span>
Answer:
step 2
Step-by-step explanation:
we have
---> given problem
step 1
Move the constant to the right side
the step 1 is correct
step 2
Complete the square
<u><em>The step 2 is not correct</em></u>
step 3
Rewrite as perfect squares
step 4
take square root both sides
step 5
Find the values of x
Answer:
Step-by-step explanation:
y = -3x - 3
m = -3_______
b = -3________
y = 2x + 2
m = 2_______
b = _2_______
SOLVE NOW : -3x - 3 = 2x + 2
- 5x = 5
x = -1
subst in y : y = 2(-1)+2 = 0
the solution is : ( - 1 , 0 )
y = -3x- 3 an equation for the line 'red'
y = 2x+2 an equation for the line 'bleus'
<h3>Answers are:
sine, tangent, cosecant, cotangent</h3>
Explanation:
On the unit circle we have some point (x,y) such that x = cos(theta) and y = sin(theta). The sine corresponds to the y coordinate of the point on the circle. Quadrant IV is below the x axis which explains why sine is negative here, since y < 0 here.
Since sine is negative, so is cosecant as this is the reciprocal of sine
csc = 1/sin
In quadrant IV, cosine is positive as x > 0 here. So the ratio tan = sin/cos is going to be negative. We have a negative over a positive when we divide.
Because tangent is negative, so is cotangent.
The only positive functions in Q4 are cosine and secant, which is because sec = 1/cos.
