Answer:
X=22
Step-by-step explanation:
The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
The Answer fam is (1/4,7/8)
Answer:
Given: Diameter of cone = 38 feet and height of cone = 14 feet.
Volume of cone V with radius r is one-third the area of the base B times the height h.
i,e
=
......[1]
,where B = 
First find the radius(r);
Using Diameter(D) = 2r
38 =2r
Divide both side by 2 we get;

Simplify:
19 = r
or r =19 feet
Now, substitute the value of r = 19 feet and h = 14 feet in [1] [ Use value of
]
then, we have:

or
V = 
or
V =
≈ 5,294.67 cubic feet.
therefore, the volume of pile is; ≈ 5,294.67 cubic feet.