Question

Need Help ASAP!!.

Answer 1

Answer:

Part 1) Greta's right, the triangle is incorrect.

Part 2) $34,203\ ft$

Part 3) The height of the tree is $23.3\ ft$, Trey’s house is not at risk

Step-by-step explanation:

Part 1) we know that

In the right triangle of the figure

$sin(30\°)=\frac{1}{2}$

$sin(30\°)=\frac{6\sqrt{3}}{12}=\frac{\sqrt{3}}{2}$

Compare

$\frac{1}{2}\neq\frac{\sqrt{3}}{2}$

therefore

The triangle is not correct

Because

The side adjacent to the 30 degree angle should be $6\sqrt{3}$ and the side opposite the 30 degree angle should be $6$

Part 2)

Let

x--------> the distance from the airplane to the SCCA (hypotenuse of the right triangle)

we know that

$sin(17\°)=\frac{10,000}{x}$

$x=\frac{10,000}{sin(17\°)}$

$x=34,203\ ft$

Part 3)

Let

x-------->  the height of the tree

we know that

$tan(43\°)=\frac{h}{25}$

$h=tan(43\°)(25)=23.3\ ft$

$23.3\ ft< 25\ ft$

therefore

Trey’s house is not at risk