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stiv31 [10]
3 years ago
7

What is the square root of 29 rounded to the nearest 10?

Mathematics
1 answer:
nydimaria [60]3 years ago
7 0
5.40. It would be 5.38 but you round up to 5.40
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What property justifies this statement
Varvara68 [4.7K]

Answer:

B. SUBTRACTION PROPERTY OF EQUALITY

Step-by-step explanation:


4 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST
Romashka [77]

Answer:

A.The mean would increase.

Step-by-step explanation:

Outliers are numerical values in a data set that are very different from the other values. These values are either too large or too small compared to the others.

Presence of outliers effect the measures of central tendency.

The measures of central tendency are mean, median and mode.

The mean of a data set is a a single numerical value that describes the data set. The median is a numerical values that is the mid-value of the data set. The mode of a data set is the value with the highest frequency.

Effect of outliers on mean, median and mode:

  • Mean: If the outlier is a very large value then the mean of the data increases and if it is a small value then the mean decreases.
  • Median: The presence of outliers in a data set has a very mild effect on the median of the data.
  • Mode: The presence of outliers does not have any effect on the mode.

The mean of the test scores without the outlier is:

   \bar{x}=\frac{Total of the observations-Outlier value}{n-1} \\=\frac{(86*16)-72}{15} \\=\frac{1304}{15}\\ =86.9333

*Here <em>n</em> is the number of observations.

So, with the outlier the mean is 86 and without the outlier the mean is 86.9333.

The mean increased.

Since the median cannot be computed without the actual data, no conclusion can be drawn about the median.

Conclusion:

After removing the outlier value of 72 the mean of the test scores increased from 86 to 86.9333.

Thus, the the truer statement will be that when the outlier is removed the mean of the data set increases.

4 0
3 years ago
Find the surface area and round to the nearest hundredths place when necessary.
pashok25 [27]

Answer:

First lets find the area of the bottom circle:

7.2 is your radius so:

7.2^2 = 51.84 the reason why you square your radius is because thats apart of the formula when finding the are of a circle.

lets continue:

51.84 x 3.14(pi) = 162.7776

Now we need to find the area of the round surface but first we need to find the circumference of one circle and multiply it by the height.

2 x 3.14 x 7.2 = 45.216

Now lets multiply it by the height:

45.216 x 17 = 768.672

Now lets add both areas:

768.672 + 162.7776 = 931.4496 dont forget to round to the nearest hundredths place! 931.4496 rounded up = 931.45 square meters is your answer.

6 0
3 years ago
. 1<br> Find f<br> for the function f.<br> f(x) = 3x² + 3, x &gt; 0<br> And find the domain
konstantin123 [22]

Answer:

y = \sqrt{\frac{x-3}{3} }

Domain = [3, infinity)

Step-by-step explanation:

x = 3y^2 + 3

3y^2 = x - 3

y^2 = (x-3)/3

y = \sqrt{\frac{x-3}{3} }

8 0
3 years ago
A market research team compiled the following discrete probability distribution, where X represents the number of automobiles ow
rodikova [14]

Answer:

The standard deviation of X is 0.7

Step-by-step explanation:

We are given the following distribution:

    x:     0        1         2       3    

P(x):    0.3     0.5     0.2     0.4

We have to find the standard deviation of X.

Formula:

E(x) = \displaystyle\sum x_iP(x_i)\\\\E(x) =0(0.3) + 1(0.5) + 2(0.2) + 3(0.4)\\\\E(x) = 2.1\\\\E(x^2) = \displaystyle\sum x_i^2P(x_i)\\\\E(x^2) =0(0.3) + 1(0.5) + 4(0.2) + 9(0.4)\\\\E(x^2) = 4.9\\\\Var(x) = E(x^2) - (E(x))^2 = 4.9-(2.1)^2 = 0.49\\\\\sigma(x) = \sqrt{Var(x)} =\sqrt{0.49} = 0.7

Thus, the standard deviation of X is 0.7

6 0
3 years ago
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