111+496= 607
1/10 + 1/10 = 2/10
607 + 2/10 = 607 and 2/10
But if youre just doing an approximate answer then...
111 = 110
496 = 500
So it would be 610
You can make 2/10 to 1/5 but that wouldnt be approx.
Your answer should be 610 and 2/10
The answer is b hope i help
Answer: A=750 +75*t
B=900 +25*t
There would be 975 students in each high school in year 3 when they are expected to have the same number of students.
Step-by-step explanation:
A = B
750 +75*t=900 + 25*t
Solving:
75*t -25*t= 900 - 750
50*t= 150
t=3
This indicates that in year 3 both High Schools are projected to have the same number of students. To get that amount, you simply replace this value in the expressions:
A=750 +75*t= 750 +75*3= 975
B=900 + 25*t=900 + 25*3= 975
There would be 975 students in each high school in year 3 when they are expected to have the same number of students.
Answer:
14
Step-by-step explanation:
when you add all the numbers together you get 14, also where you put the line you can see that the line is a 3 and 5 minus 2 is 3. The next corner next to the 3 is 1 cm because if you look at the horizontal 2 it matches up with the horizontal 1 and 2 minus 1 is 1.
