For this case we must simplify the following expression:
![6 (1 + 8n) = - 39 + 3n](https://tex.z-dn.net/?f=6%20%281%20%2B%208n%29%20%3D%20-%2039%20%2B%203n)
We apply distributive property on the left side of the equation:
![6 * 1 + 6 * 8n = -39 + 3n\\6 + 48n = -39 + 3n](https://tex.z-dn.net/?f=6%20%2A%201%20%2B%206%20%2A%208n%20%3D%20-39%20%2B%203n%5C%5C6%20%2B%2048n%20%3D%20-39%20%2B%203n)
We subtract 3n from both sides of the equation:
![6 + 48n-3n = -39\\6 + 45n = -39](https://tex.z-dn.net/?f=6%20%2B%2048n-3n%20%3D%20-39%5C%5C6%20%2B%2045n%20%3D%20-39)
We subtract 6 from both sides of the equation:
![45n = -39-6\\45n = -45](https://tex.z-dn.net/?f=45n%20%3D%20-39-6%5C%5C45n%20%3D%20-45)
We divide between 45 on both sides of the equation:
![n = \frac {-45} {45}\\n = -1](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%20%7B-45%7D%20%7B45%7D%5C%5Cn%20%3D%20-1)
Answer:
![n = -1](https://tex.z-dn.net/?f=n%20%3D%20-1)
The next number in this pattern should be A)28
Answer:
A. (0,-1)
Step-by-step explanation:
The equation for this problem is y=1/2x-1
Value of the expression will be 7
<u><em>Explanation</em></u>
Given value of the variables are :
and ![q=7](https://tex.z-dn.net/?f=q%3D7)
Given expression: ![8p+3q-18](https://tex.z-dn.net/?f=8p%2B3q-18)
So, <u>plugging the values</u> of
and
into the above expression, we will get...
![8p+3q-18\\ \\ = 8(\frac{1}{2})+3(7)-18\\ \\ =4 + 21-18\\ \\ =25-18\\ \\ =7](https://tex.z-dn.net/?f=8p%2B3q-18%5C%5C%20%5C%5C%20%3D%208%28%5Cfrac%7B1%7D%7B2%7D%29%2B3%287%29-18%5C%5C%20%5C%5C%20%3D4%20%2B%2021-18%5C%5C%20%5C%5C%20%3D25-18%5C%5C%20%5C%5C%20%3D7)
So, the value of the expression will be 7.
Answer:
see attachment
Step-by-step explanation:
The directions tell you what you need to know. It is a matter of adding up the values shown and finding the missing number to make the total be -20. Of course, it works best to start with a row, column, or diagonal that has 4 numbers already.Then, you're only finding the 5th number.
You can start with either diagonal, column 1 or 4, and row 4 or 5. Filling the missing numbers in those spots (red) will let you find the remaining missing numbers (green, then blue).
The square at row 2, column 2 can be filled on the first round using the down-right diagonal. I have shown it as filled on the second round after row 5 column 2 is filled.
Using a spreadsheet can make this easier, because you can write formulas for the sums in each row, column, and diagonal. Then you're just making those sums be -20.
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For example, consider the up-right diagonal. The sum of the given values, -6, 0, -4, -2, is -12. Then the spot at row 1, column 5 must be filled with -8 to make the sum be -20.