The measures of spread include the range, quartiles and the interquartile range, variance and standard deviation. Let's consider each one by one.
<u>Interquartile Range: </u>
Given the Data -> First Quartile = 2, Third Quartile = 5
Interquartile Range = 5 - 2 = 3
<u>Range:</u> 8 - 1 = 7
<u>Variance: </u>
We start by determining the mean,
n = number of numbers in the set
Solving for the sum of squares is a long process, so I will skip over that portion and go right into solving for the variance.
5.3
<u>Standard Deviation</u>
We take the square root of the variance,
2.3
If you are not familiar with variance and standard deviation, just leave it.
<span>1220
Subtracting the lower boundary of 1492 grams from the mean of 3234 gives you 1742 grams below the mean. Dividing 1742 by the standard deviation of 871 gives you 2 standard deviations below the curve. Now doing the same with the upper limit of 4976 grams also gives you 2 standard deviations above the mean (4976-3234)/871 = 2
So you now look for what percentage of the population lies within 2 standard deviations of the mean. Standard lookup tables will indicate that 95.4499736% of the population will be within 2Ď of the mean. So multiply 1278 by 0.954499736 giving 1219.851. Then round to the nearest whole number and you have an estimated 1220 babies that weigh between 1492 grams and 4976 grams.</span>
Answer:
I've never done this before, but if it is balls per square foot, then i can figure it out. It is 2 balls per square foot
Step-by-step explanation:
If the gym is 100 ft by 60 ft, it will be 6,000 square ft. Since there are 12,000 balls, you divide it by 6,000 (12,000/6,000), which is 2, so it would be 2 balls per square foot
Answer:
Option a)
Step-by-step explanation:
To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.
Then. x = 2 it's a vertical asintota.
To obtain the horizontal asymptote of the function take the following limit:
if 
then y = b is horizontal asymptote
Then:
Therefore y = 0 is a horizontal asymptote of f(x).
Then the correct answer is the option a) x = 2, y = 0
Answer:
In Weston 1,296 males are married
Step-by-step explanation:
step 1
Find out the number of males
Multiply the total population by 45%
step 2
Find out the number of males that are married
Multiply the number of males by 2/3
therefore
In Weston 1,296 males are married
