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Mekhanik [1.2K]
4 years ago
5

How do you put 4.110 in words

Mathematics
2 answers:
gogolik [260]4 years ago
6 0
Four and one hundred ten thousandths is the pronunciation for 4.110.
Eva8 [605]4 years ago
4 0
Four point one one zero
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Consider this equation:  2/3 x − 9 − 2x + 2 = 1
Mekhanik [1.2K]
-4/3x (or -1 1/3x if you use whole numbers instead of an improper fraction) -7 = 1
6 0
3 years ago
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Which terms could be used as the first term of the expression below to create a polynomial written in standard form? Select five
Alina [70]

Answer:

3r⁴s⁵

- r⁴s⁶

- 6rs⁵

Step-by-step explanation:

1) The expression given is:

+ 8r²s⁴ – 3r³s³

2) The choices given are:

s⁵

3r⁴s⁵

- r⁴s⁶

- 6rs⁵

1) A polynomial written in standard form has the terms ordered in decreasing order.

For example, 4x⁵ + 8x⁴ + 3x² + 27

2) The given polynomial has degree 6: + 8r²s⁴ – 3r³s³, and it can be ordered respect any of the two variables either r or s.

3)  Adding a new term as first term needs to have degree equal or greater than 6.

So, the candidates from the list are: 3r⁴s⁵, - r⁴s⁶,- 6rs⁵

4) If you use 3r⁴s⁵, the polynomial in standard form would be:

3r⁴s⁵ – 3r³s³ + 8r²s⁴ (as you see the degree of r is decreasing from left to right).

5) If you use - r⁴s⁶, the polynomial in standard form would be:

- r⁴s⁶ – 3r³s³ + 8r²s⁴ (as you see, the degree of r decreases from left to right)

6) If you use - 6rs⁵, the polynomial in standard form would be

- 6 rs⁵– 3r³s³ + 8r²s⁴ (as you see the degree of s is decreasing from left to right).

7) You cannot use s⁵ as first term because its degree is less than 6.

3 0
3 years ago
Read 2 more answers
Find the taylor polynomial t3(x) for the function f centered at the number
inysia [295]

Answer:

t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3

Step-by-step explanation:

We are given that

f(x)=7tan^{-1}(x)

a=1

T_n(x)=\sum_{r=0}^{n}\frac{f^r(a)(x-a)^r}{r!}

Substitute n=3 and a=1

t_3(x)=f(1)+f'(1)(x-1)+\frac{f''(1)(x-1)^2}{2!}+\frac{f'''(1)(x-1)^3}{3!}

f(x)=7tan^{-1}(x)

f(1)=7tan^{-1}(1)=7\times \frac{\pi}{4}=\frac{7\pi}{4}

Where tan^{-1}(1)=\frac{\pi}{4}

f'(x)=\frac{7}{1+x^2}

Using the formula

\frac{d(tan^{-1}(x))}{dx}=\frac{1}{1+x^2}

f'(1)=\frac{7}{2}

f''(x)=\frac{-14x}{(1+x^2)^2}

f''(1)=-\frac{7}{2}

f''(x)=-14x(x^2+1)^{-2}

f'''(x)=-14((x^2+1)^{-2}-4x^2(x^2+1)^{-3}})

By using the formula

(uv)'=u'v+v'u

f'''(x)=-14(\frac{x^2+1-4x^2}{(1+x^2)^3}

f'''(x)=(-14)\frac{-3x^2+1}{(1+x^2)^3}

f'''(1)=-14(\frac{-3(1)+1}{2^3})=\frac{7}{2}

Substitute the values

t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{2\times 3\times 2\times 1}(x-1)^3

t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3

7 0
3 years ago
If a1 = 7 and an = An-1 – 3 then find the value of a4.
V125BC [204]

Answer:

-2

Step-by-step explanation:

If a1 = 7 and an = An-1 – 3

a4 = a3 - 3

Get a2;

a2 = a1 - 3

a2 = 7 - 3

a2 = 4

Get a3;

a3 = a2 - 3

a3 = 4 - 3

a3 = 1

GEt the required a4

a4 = a3 - 3

a4 = 1 - 3

a4  = -2

Hence the value of a4 is -2

8 0
3 years ago
****The last one was multiply each side by 62<br><br> Someone please help ASAP
navik [9.2K]

Answer:

Add 62 to each side

Step-by-step explanation:

8 0
3 years ago
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