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3 years ago

How do you put 4.110 in words

Mathematics

2 answers:

gogolik [260]3 years ago

6 0

Four and one hundred ten thousandths is the pronunciation for 4.110.

Eva8 [605]3 years ago

4 0

Four point one one zero

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PLESE HELP ill GIVE BRANILY Solve for x. 3.5(7-x)+32=106-1.5(4x+18)

murzikaleks [220]

Answer:

X=9

Step-by-step explanation:

3.5(7−x)+32=106−1.5(4x+18)

Step 1: Simplify both sides of the equation.

3.5(7−x)+32=106−1.5(4x+18)

(3.5)(7)+(3.5)(−x)+32=106+(−1.5)(4x)+(−1.5)(18)(Distribute)

24.5+−3.5x+32=106+−6x+−27

(−3.5x)+(24.5+32)=(−6x)+(106+−27)(Combine Like Terms)

−3.5x+56.5=−6x+79

Step 2: Add 6x to both sides.

−3.5x+56.5+6x=−6x+79+6x

2.5x+56.5=79

Step 3: Subtract 56.5 from both sides.

2.5x+56.5−56.5=79−56.5

2.5x=22.5

Step 4: Divide both sides by 2.5.

2.5x

2.5

22.5

2.5

x=9

4 0

3 years ago

Read 2 more answers

For the following right triangle, find the side length x. Round your answer to the nearest hundredth.

atroni [7]

Answer:

14.97

Step-by-step explanation:

8 0

2 years ago

The Talbot family got 2 pizzas and 4 drinks for $32. The Martinez family got 3 pizzas and 8 drinks for $52. How much does each p

Brrunno [24]

Answer:

Each pizza costs $12.

Each drink costs $2.

Step-by-step explanation:

This question can be solved using a system of equations.

I am going to say that:

x is the cost of each pizza.

y is the cost of each drinks.

The Talbot family got 2 pizzas and 4 drinks for $32.

This means that $2x + 4y = 32$

The Martinez family got 3 pizzas and 8 drinks for $52.

This means that $3x + 8y = 52$

Using the addition method, multiplying the first equation by -2.

-4x - 8y = -64

3x + 8y = 52

-4x + 3x - 8y + 8y = -64 + 52

-x = -12

x = 12

Each pizza costs $12.

2x + 4y = 32

4y = 32 - 2x

4y = 32 - 2*12

4y = 8

y = 2

Each drink costs $2.

5 0

3 years ago

Is 90ft bigger than 32 yards

JulsSmile [24]

No, 90 feet is NOT bigger than 32 yards.

An easy way to solve this is to convert feet to yards, or vice versa.

1 yard = 3 feet

32 × 3 = 96 feet

Now, put that into the problem and try and solve it.
Is 90 feet bigger than 96 feet? The answer is NO because 90 < 96.

6 0

2 years ago

Read 2 more answers

Find the mass and the center of mass of a wire loop in the shape of a helix (measured in cm: x = t, y = 4 cos(t), z = 4 sin(t) f

Sholpan [36]

Answer:

Mass

$\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)$

Center of mass

Coordinate x

$\displaystyle\frac{(\displaystyle\frac{(2\pi)^4}{4}+32\pi)}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

Coordinate y

$\displaystyle\frac{16\pi}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

Coordinate z

$\displaystyle\frac{-16\pi}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

Step-by-step explanation:

Let W be the wire. We can consider W=(x(t),y(t),z(t)) as a path given by the parametric functions

x(t) = t

y(t) = 4 cos(t)

z(t) = 4 sin(t)

for 0 ≤ t ≤ 2π

If D(x,y,z) is the density of W at a given point (x,y,z), the mass m would be the curve integral along the path W

$m=\displaystyle\int_{W}D(x,y,z)=\displaystyle\int_{0}^{2\pi}D(x(t),y(t),z(t))||W'(t)||dt$

The density D(x,y,z) is given by

$D(x,y,z)=x^2+y^2+z^2=t^2+16cos^2(t)+16sin^2(t)=t^2+16$

on the other hand

$||W'(t)||=\sqrt{1^2+(-4sin(t))^2+(4cos(t))^2}=\sqrt{1+16}=\sqrt{17}$

and we have

$m=\displaystyle\int_{W}D(x,y,z)=\displaystyle\int_{0}^{2\pi}D(x(t),y(t),z(t))||W'(t)||dt=\\\\\sqrt{17}\displaystyle\int_{0}^{2\pi}(t^2+16)dt=\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)$

The center of mass is the point $(\bar x,\bar y,\bar z)$

where

$\bar x=\displaystyle\frac{1}{m}\displaystyle\int_{W}xD(x,y,z)\\\\\bar y=\displaystyle\frac{1}{m}\displaystyle\int_{W}yD(x,y,z)\\\\\bar z=\displaystyle\frac{1}{m}\displaystyle\int_{W}zD(x,y,z)$

We have

$\displaystyle\int_{W}xD(x,y,z)=\sqrt{17}\displaystyle\int_{0}^{2\pi}t(t^2+16)dt=\\\\=\sqrt{17}(\displaystyle\frac{(2\pi)^4}{4}+32\pi)$

$\bar x=\displaystyle\frac{\sqrt{17}(\displaystyle\frac{(2\pi)^4}{4}+32\pi)}{\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)}=\displaystyle\frac{(\displaystyle\frac{(2\pi)^4}{4}+32\pi)}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

$\displaystyle\int_{W}yD(x,y,z)=\sqrt{17}\displaystyle\int_{0}^{2\pi}4cos(t)(t^2+16)dt=\\\\=16\sqrt{17}\pi$

$\bar y=\displaystyle\frac{16\sqrt{17}\pi}{\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)}=\displaystyle\frac{16\pi}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

$\displaystyle\int_{W}zD(x,y,z)=4\sqrt{17}\displaystyle\int_{0}^{2\pi}sin(t)(t^2+16)dt=\\\\=-16\sqrt{17}\pi$

$\bar z=\displaystyle\frac{-16\sqrt{17}\pi}{\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)}=\displaystyle\frac{-16\pi}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

3 0

2 years ago