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marshall27 [118]
2 years ago
12

Find the area of these shapes

Mathematics
1 answer:
alexira [117]2 years ago
7 0

Answer:

Step-by-step explanation:

Left figure:

area of rectangle = 4×6 = 24 cm²

area of triangle = ½×(base of triangle)×(height of triangle) = ½×6×4  = 12 cm²

area of shape = 24+12 = 36 cm²

Right figure:

area of rectangle = 6×8 = 48 m²

area of triangle = ½×(base of triangle)×(height of triangle) = ½×8×(8-6) = 8 m²

area of shape = 48+8 = 56 m²

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Answer:

infinetly many solutions

Step-by-step explanation:

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3 years ago
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Find the height <br> 11in 14in<br> h=
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Answer:

h = \sqrt{72}in

Step-by-step explanation:

We have a right triangle with long side of 11in and smaller sides 14in/2=7in and h.

We know that

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6 0
3 years ago
Can someone please help with #16
ollegr [7]

Answer:

∠ WZX = 50°

XW is not an altitude.

Step-by-step explanation:

16. See the attached figure.

XW is the angle bisector of ∠ YXZ, hence, ∠ WXY = ∠ WXZ

Now, given that ∠ YXZ = 8x + 34 and ∠ WXY = 10x - 13

Hence, ∠ YXZ = 2 ∠ WXY

⇒ 8x + 34 = 2(10x - 13)

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⇒ 12x = 60

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Hence, ∠ XZY = ∠ WZX = 10x = 50° (Answer)

Now, ∠ WXZ = ∠ WXY = 10x - 13 = 37°

Hence, from Δ WXZ,

∠ WZX + ∠ WXZ + ∠ XWZ = 180°

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6 0
3 years ago
In the morning, the temperature was 15∘F. During the day, the temperature fell 37 degrees. Which expression shows how to find th
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2 years ago
Anybody know the answer??
Nady [450]

If you solve for theta, it would be 3pi/4

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