2617 to the nearest thousand
2 answers:
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Answer:
(10.78483, 12.61517)
Step-by-step explanation:
It is given that the genera mangers of few hotels were sent some questionnaires for conducting a study for the career paths in the major hotel chains of the United States.
Number of hotels = 160
Number of response received = 103
The average number of years these general mangers was in their current hotels, = 11.7 years
Confidence Interval, CI = 0.99
Therefore,
a = 0.01, |Z(0.005)| (from standard normal table)
∴ 99% of CI =
Answer:
Step-by-step explanation:
It would be more obvious if it says z is a standard Normal variable and that the question is related to statistics.
From "Computing Probabilities Using the Cumulative Table" , the probability of z is less than 1.16, P(z<1.16) = 0.8770.
