We know that in the triangle ACB ∠ACB+90+34=180-----> ∠ACB=180-(90+34)----> ∠ACB=56° ∠ACD and ∠ACB-----> are supplementary angles so ∠ACD+∠ACB=180-----> ∠ACD=180-56----> 124°------> x=124°
the answer Part 1) is x=124°
Part 2) ∠ACB+∠BCF+80=180-----> ∠BCF=180-(∠ACB+80)---> 180-(56+80) ∠BCF=180-136----> 44°-----> y=44°