Let x represent the measure of angle ACD, and let y represent the measure of angle BCF.

Mathematics

1 answer:

Liono4ka [1.6K]3 years ago

5 0

We know that
in the triangle ACB
∠ACB+90+34=180-----> ∠ACB=180-(90+34)----> ∠ACB=56°
∠ACD and ∠ACB-----> are supplementary angles
so
∠ACD+∠ACB=180-----> ∠ACD=180-56----> 124°------> x=124°

the answer Part 1) is x=124°

Part 2)
∠ACB+∠BCF+80=180-----> ∠BCF=180-(∠ACB+80)---> 180-(56+80)
∠BCF=180-136----> 44°-----> y=44°

the answer Part 2) is y=44°

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The area of a trapezium is 800 cm2

svlad2 [7]

Answer:

The distance between the parallel sides is 20cm.

Step-by-step explanation:

Area of a trapezoid:

$A=\frac{a+b}{2}\times h$

where a and b are the 2 bases, and h is the height. The value we're trying to find here is the height.

3 of the 4 variables in this equation are already given:

A = 800

a = 48

b = 32

Just plug those in and solve for h:

$\rightarrow 800=\frac{48+32}{2}\times h\\\rightarrow 800=\frac{80}{2}\times h\\\rightarrow 800=40\times h\\\rightarrow 800\div40=h\\\rightarrow h=20$