Explanation:
Species of rats are found throughout the order Rodentia, but stereotypical rats are found in the genus Rattus. Other rat genera include Neotoma (pack rats), Bandicota (bandicoot rats) and Dipodomys (kangaroo rats). Rats are typically distinguished from mice by their size.
Answer:
a. Glycolysis
b. actually, both plants and animals use glycolysis. They use these during cellular respiration and plant respiration
c. Heart tissue!
Explanation:
a. Glycolysis produces 2 ATP per glucose molecule, and thus provides a direct means of producing energy in the absence of oxygen. Lactic acid, the end product of anaerobic glycolysis.
b. In organisms that perform cellular respiration, glycolysis is the first stage of this process. In plants, this metabolic process occurs in the cytosol and plastids of both photosynthetic and non-photosynthetic organs.
c. Pyruvate is an important chemical compound in biochemistry. It is the output of the metabolism of glucose known as glycolysis. In highly oxidative tissue, such as the heart, the production of pyruvate is essential for acetyl-CoA synthesis and L-malate synthesis.
Hope this helps! If you could, please mark this as brainliest :)
Answer:
7.5cm
Explanation:
Velocity vs Time Graph:
When the object is going along the plane with velocity v at a particular time interval t we can explain it's motion via the velocity vs time graph. If the velocity of the object is constant then velocity vs time graph will produce a horizontal straight line. If the amount of differentiation of velocity of the object is positive and constant then the graph shows the linear line whose slope is is the same as the ratio of the change in velocity to the time interval.
Velocity vs time graph:
Is shown in the attached image
A velocity-time graph helps us to estimate the distance traveled by using the area under the graph.
Height of the triangle is the velocity (v) = 0.75m/s
The base of the triangle is the time interval (t) = 0.2sec
Distance travelled = Area of triangle
Distance travelled
= 1/2(V) * t
= 1/2(0.75m/s) * 0.2s
= 0.0075m
=7.5cm
Thus, during one beat blood flows 7.5 cm
