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Ostrovityanka [42]
3 years ago
10

Solve each system by elimination. -8x14y=-14. 5x+7y=0help me solve this please.

Mathematics
2 answers:
katrin2010 [14]3 years ago
8 0
The answer is (7/9, -5/9)

(7 over 9 and negative 5 over 9)
kirill115 [55]3 years ago
4 0
(7/9, -5/9) is the answer
You might be interested in
Please Help I don't understand how to do this!
liraira [26]

Answer:

  c.  Look at the first 7 digits in the table. Let digits from 0 to 3 ...

Step-by-step explanation:

The digits in a random number table are intended to be uniformly distributed, so that each digit has a probability of 0.1. By using combinations of digits you can fairly easily define an outcome that has a probability that is a multiple of 0.1.

Here, you want a probability of 40% = 0.4 = 4×0.1. By defining your outcome as any of 4 digit values, (0 to 3, for example), that outcome will have a probability of 0.4 = 40% when a digit is randomly chosen.

To choose the correct answer here, you only need to understand the above, then choose the answer choice that has an outcome that is defined as 4 of the digits.

___

By looking at 7 digits, you effectively run a simulation in which you do the trial 7 times. Here, you're buying 7 boxes of cereal, so you're interested in 7 trials, each with a probability of success of 40%. This further confirms that the answer choice should include the wording "look at the first 7 digits."

___

<em>More explanation</em>

If the first digit is a number 0-3, it means you got a toy in the first box of cereal.

If the second digit is a number 0-3, it means you got a toy in the second box of cereal.

...

If the 7th digit is a number 0-3, it means you got a toy in the 7th box of cereal.

By counting the number of digits of the first 7 digits that are in the range 0-3, you are effectively counting the number of toys you got in those 7 boxes of cereal.

For example, if the first 7 digits of the table are 9656369*, there is only 1 digit in the range 0-3. That means this purchase of 7 boxes of cereal resulted in 1 toy.

_____

In order to answer Lydia's question, many groups of 7 digits would need to be evaluated, and the ratio of 2-toy purchases to total purchases computed from those results. A trial involving 7000 digits resulted in 268 purchases out of 1000 that had exactly 2 toys, for an experimental probability of 26.8%. Using the binomial distribution, the theoretical probability is about 26.1%--a fairly good match.

___

* this number was generated by random [dot] org

7 0
4 years ago
5/22 is that rational number
PIT_PIT [208]
Yes because 5/22 is 4 2/5 and that equals .4
3 0
3 years ago
I’m having trouble with this question I need some help please
vivado [14]

Answer:

\frac{1}{2}  \:  \:  \:  \:  \:  \frac{1}{4 \: }  \:  \:  \:  \frac{1}{8}

\frac{4}{8}  \:  \:  \:  \frac{2}{8}  \:  \:  \:  \frac{1}{8}

She ate

\frac{7}{8}

8 0
3 years ago
15/7 plus 2/3plus 1/6
scoundrel [369]

Answer:

125/42

Step-by-step explanation:

15/7 + 2/3 + 1/6

90/42 + 28/42 + 7/42

125/42

2.976

4 0
3 years ago
Read 2 more answers
Help!! 50 points and brainliest!
Viktor [21]

Answer:

Second choice:

x=2t

y=4t^2+4t-3

Fifth choice:

x=t+1

y=t^2+4t

Step-by-step explanation:

Let's look at choice 1.

x=t+1

y=t^2+2t

I'm going to subtract 1 on both sides for the first equation giving me x-1=t. I will replace the t in the second equation with this substitution from equation 1.

y=(x-1)^2+2(x-1)

Expand using the distributive property and the identity (u+v)^2=u^2+2uv+v^2:

y=(x^2-2x+1)+(2x-2)

y=x^2+(-2x+2x)+(1-2)

y=x^2+0+-1

y=x^2

So this not the desired result.

Let's look at choice 2.

x=2t

y=4t^2+4t-3

Solve the first equation for t by dividing both sides by 2:

t=\frac{x}{2}.

Let's plug this into equation 2:

y=4(\frac{x}{2})^2+4(\frac{x}{2})-3

y=4(\frac{x^2}{4})+2x-3

y=x^2+2x-3

This is the desired result.

Choice 3:

x=t-3

y=t^2+2t

Solve the first equation for t by adding 3 on both sides:

x+3=t.

Plug into second equation:

y=(x+3)^2+2(x+3)

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

y=(x^2+6x+9)+(2x+6)

y=(x^2)+(6x+2x)+(9+6)

y=x^2+8x+15

Not the desired result.

Choice 4:

x=t^2

y=2t-3

I'm going to solve the bottom equation for t since I don't want to deal with square roots.

Add 3 on both sides:

y+3=2t

Divide both sides by 2:

\frac{y+3}{2}=t

Plug into equation 1:

x=(\frac{y+3}{2})^2

This is not the desired result because the y variable will be squared now instead of the x variable.

Choice 5:

x=t+1

y=t^2+4t

Solve the first equation for t by subtracting 1 on both sides:

x-1=t.

Plug into equation 2:

y=(x-1)^2+4(x-1)

Distribute and use the binomial square identity used earlier:

y=(x^2-2x+1)+(4x-4)

y=(x^2)+(-2x+4x)+(1-4)

y=x^2+2x+-3

y=x^2+2x-3.

This is the desired result.

3 0
4 years ago
Read 2 more answers
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