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REY [17]
3 years ago
5

{x{ x + 4<0 or 6x>-12)

Mathematics
1 answer:
lora16 [44]3 years ago
4 0

Answer:

x\in (-\infty , -4) \cup (-2,+\infty)

Step-by-step explanation:

Solve the system of inequalities:

x + 4 < 0

OR:

6x > -12

The first inequality yields the solution:

x < -4

The second inequality gives the solution:

x > -2

The total solution is the disjunction of the individual solutions, i.e., the union of both.

It can be expressed as

\mathbf{x\in (-\infty , -4) \cup (-2,+\infty)}

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For the function g(x) = x – 2x^2, find g (–3) + 13
svp [43]

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