The absolute value equation written by Edwin according to his intention in the task content is; |x -3.9| = 0.3 and The values that are 0.3unuts from 3.9 are; 4.2 and 3.6.
<h3>What absolute value equation can be written by Edwin to find the numbers which are 0.3 units away from 3.9 on the number line?</h3>
Since the numbers in discuss are required to be 0.3 units from 3.9, it follows that one number is greater while the other is less than 3.9 and hence the required absolute value equation is;
|x -3.9| = 0.3. which can be solved as;
x-3.9 = 0.3; x =4.2.
Or
x -3.9 = -0.3; x = 3.6.
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Yes, that's the definition of "midpoint."
xa + xb
xmidpoint = --------------
2
ya + yb
ymidpoint = --------------
2
If the question is how much does it cost for 4 lines plus a one-time advertising fee than your answer is $36.
