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3 years ago

Recognizing the no-solution case algebraically need geometry help!!

Mathematics

1 answer:

Dmitrij [34]3 years ago

6 0

Answer:

"The values for y are square roots of negative numbers"

Step-by-step explanation:

The steps shown are correct. But at the end we can see that we have to "take the negative square roots".

This means we have to take the square root of -1. In the real number system, we CANNOT take the square root of any negative number. Hence, there is NO SOLUTION to the system.

2nd answer choice, "The values for y are square roots of negative numbers", is right.

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Dr.Bradley said that my cat Pumpkin was too heavy at 17 pounds and that he should lose weight.After three months on a cat weight

Alexxandr [17]

Answer: The percentage changes is $-11\frac{13}{17} \%$

Step-by-step explanation:

Since the initial weight of the dog = 17 pounds,

After 3 months, the weight of the dog = 15 pounds,

⇒ $\text{ The percentage in the weight of the dog} = \frac{\text{ Initial weight-final weight}}{\text{ initial weight}}\times 100$

⇒ $\text{ The percentage in the weight of the dog} = \frac{15-17}{17}\times 100$

= $-\frac{2}{17}\times 100$

= $-\frac{200}{17}$

= $-11\frac{13}{17}\%$

3 0

4 years ago

Determine the equivalent system for the given system of equations. 4x - 5y = 2 3x - y = 8

kondor19780726 [428]

4x − 5y = 2
7x + 6y = 10

4 0

3 years ago

What is the greatest number which can be made using each of the digits 5,3,1,4,7

Minchanka [31]

That is tricky but I multiplied them all and got 420 I hope that helps. :)

5 0

3 years ago

Read 2 more answers

Who can help me 10, 11, 12, 13,and 14

NeTakaya

11: 6(3x+4y)
13a: 5x(3-4y)
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8 0

4 years ago

A population has a mean muequals160 and a standard deviation sigmaequals20. Find the mean and standard deviation of the sampling

hoa [83]

Answer:

Mean 160

Standard deviation 2.63

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 160, \sigma = 20$

Find the mean and standard deviation of the sampling distribution of sample means with sample size n = 58.

Mean 160

Standard deviation $s = \frac{20}{\sqrt{58}} = 2.63$

6 0

4 years ago