Recognizing the no-solution case algebraically need geometry help!!

Mathematics

1 answer:

Dmitrij [34]3 years ago

6 0

Answer:

"The values for y are square roots of negative numbers"

Step-by-step explanation:

The steps shown are correct. But at the end we can see that we have to "take the negative square roots".

This means we have to take the square root of -1. In the real number system, we CANNOT take the square root of any negative number. Hence, there is NO SOLUTION to the system.

2nd answer choice, "The values for y are square roots of negative numbers", is right.

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y = 6t - 1/2(9.8)t^2 + 12
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d.) At the time the ball reaches the ground, y = 0
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Answer:

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