Answer:
not completely sure but I think it's it's 13.4
Let's divide the shaded region into two areas:
area 1: x = 0 ---> x = 2
ares 2: x = 2 ---> x = 4
In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.
Area 1:
Area 2:
Therefore, the area of the shaded portion of the graph is
A = A1 + A2 = 5.34
What is the interquartile range of the data set below? Growth in feet of oak trees: 68,80,73,90,120,94,76,112,101,94,72 (1) 22
sdas [7]
<span>68,80,73,90,120,94,76,112,101,94,72 --->
68, 72, 73, 76, 80, 90, 94, 94, 101, 112, 120
Median = 90
Lower Median = 73
Upper Median = 101
IQR = 101 - 73
IQR = 28</span>
Answer:
D; x -y = 22
3x + 2y = 246
Step-by-step explanation:
Let us have the bigger number as x and the smaller as y
The difference between the two is 22
Thus, we have it that;
x - y = 22
twice the smaller number; 2(y) added to thrice the larger 3(x) equals 246
3x + 2y = 246
So we have the two equations as;
x -y = 22
3x + 2y = 246
