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dalvyx [7]
3 years ago
9

Jane bought 4 books, 3 cups, and 7 rungs. She paid $4 per book, $5 per cup, and $10 per ring. Estimate her change from $50 bill

after buying the books and cups only?
Mathematics
2 answers:
vlada-n [284]3 years ago
8 0

Hello!

Let's multiply each thing here.

4(4)=16

3(5)=15

15=16=31

50-31=29

Therefore, her change is $29.

I hope this helps!

uysha [10]3 years ago
5 0

$29 is the change from the $50 bill

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3 0
3 years ago
A researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playi
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Answer:

Proportion of the students recalled more than 15 names is 91.77%.

Step-by-step explanation:

We are given that a researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playing the name game, the students were asked to recall as many first names of fellow students as possible.

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<em>Let X = number of names recalled</em>

SO, X ~ N(\mu = 19.41,\sigma^{2} = 3.17^{2})

The z-score probability distribution is given by ;

                  Z = \frac{X-\mu}{\sigma} } } ~ N(0,1)

where, \mu = mean number of names recalled = 19.41

            \sigma = standard deviation = 3.17

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, proportion of the students recalled more than 15 names is given by = P(X > 15 names)

     P(X > 15) = P( \frac{X-\mu}{{\sigma} } } > \frac{15-19.41}{3.17}  } ) = P(Z > -1.39)

                                                      = P(Z < 1.39) = 0.9177  {using z table}

<em>Therefore, proportion of the students recalled more than 15 names is </em><em>91.77%.</em>

4 0
3 years ago
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Dovator [93]
<h3>Answer:  B) 2</h3>

=========================================================

Explanation:

Take away the four white small squares on the left side. To balance things out, you have to add 4 black squares to the right side.

Also, take away the two white long rectangles from the right side. To balance this out, you have to add 2 gray long rectangles to the left side.

You should have:

  • 5 gray rectangles, and no squares (of any color) on the left side
  • 10 black squares, no long rectangles (of any color), on the right side

From here you'll group up the 10 black squares so that you'll have 2 black squares per gray rectangle.

This means the solution is 2.

-------------------------------------

If you're curious about the algebraic way to solve, then you could do this:

3x-4 = -2x+6

3x+2x = 6+4

5x = 10

x = 10/5

x = 2

This method doesn't require us to use the visual model.

5 0
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