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nikdorinn [45]
3 years ago
14

If num is an int which expression always evaluates to true if num holds an odd number

Computers and Technology
1 answer:
tatyana61 [14]3 years ago
8 0

The answer is 2) Num%2==1.
The modulus operator (%) divides the left hand side by the right hand side and returns the remainder.

Examples:
3%2=1 : 2 goes into 3 once, with 1 remaining.

5%2 =1 :  2 goes into 5 twice, with 1 remaining.

11%2 =1 :  2 goes into 11 five times, with 1 remaining.

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Elanso [62]

It might because of many reasons:

  • Fan 1 is not connected to the Program (via Bluetooth, WIFI, or wired)
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4 0
3 years ago
Digital signatures are as legally acceptable as written signatures.
Leto [7]

Answer:

First point and the last point are the correct answer to the given question .

Explanation:

The main objective of the digital signature is to ensure the quality of the document or the message was not changed during the transfer of message in the network.

Following are the advantages of the digital signature

  • As compare to the electronic signature the digital signature is more secure then that of.
  • The signer's signature is seen on the digital signatures as the physical proof.
  • Global recognition, and the compliance with the law.

All the other options are incorrect they are not advantage of the digital signature .

4 0
3 years ago
Write a function that receives two numbers, m and n and calculates and displays the sum of the integers from m to n. For example
Evgesh-ka [11]

Answer:

The program to this question as follows:

Program:

//header file

#include <stdio.h> //defining header file

void inc(int m,int n) //defining method inc

{

   int sum, i; //declaring variable

   sum=m; //holding value of m variable

   for(i=++m;i<=n;i++) //loop for calculate number between given range  

   {

   sum=sum+i; //adding value

   }

   printf("sum of the integer is : %d",sum);//print value

}

int main() //defining method

{

   int m,n; //defining integer variable

   printf("Enter m value: "); //message

   scanf("%d",&m); //input value by user in variable

   printf("Enter n value: "); //message

   scanf("%d",&n);//input value by user in variable

   inc(m,n); //calling method

   return 0;

}

Output:

Enter m value: 3

Enter n value: 7

sum of the integer is :25

Explanation:

In the above code, an "inc" function is declared, that accepts integer parameters that are "m and n", inside the method two integer variable "sum and i" is declared, which is used in the loop.

  • The loop uses the user parameter to count value and uses the sum variable to calculate there sum.
  • In the main method, two integer variable n and m are declared, which take value from the user end, and at the last, we call the inc method, that prints sum value.
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Answer:

Option 1,4 and 5 are correct.

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