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3 years ago

I need help can anyone help me

Mathematics

2 answers:

leva [86]3 years ago

6 0

Answer:

Step-by-step explanation:

move every point down by four and those will be your new coordinates

goldenfox [79]3 years ago

5 0

Answer:

D. H (-5,-2) J(-3,-5)K(2,-1)

Step-by-step explanation:

move k down 4 (2,-1)

Like or leave a comment :) have a good one

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3 years ago

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Find f(-3) if f (x) =|x+5|

vesna_86 [32]

Answer:

the answer is two because the absolute value delete the negative in result not in question

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2 years ago

PLEASE ANSWER !!

ANEK [815]

Answer:

Check the explanation.

Step-by-step explanation:

As the graph of a linear function f passes through the point (-2,-10) and has a slope of 5/2.

As the slop-intercept form is given by:

$y = mx+b$

where m is the slope and b is the y-intercept.

substituting the values (-2, -10) and m = 5/2 in the slop-intercept form to determine y-intercept.

$y = mx+b$

$-10=\frac{5}{2}\left(-2\right)+b$

$-\frac{5}{2}\cdot \:2+b=-10$

$-5+b=-10$

$-5+b+5=-10+5$

$b=-5$

And the equation of the line in the slope-intercept form will be:

$y = mx+b$

putting b = -5 and slope = m = 5/2

$y = mx+b$

$y=\frac{5}{2}x+\left(-5\right)$

$y=\frac{5}{2}x-5$

Determining the zero of function.

As we know that the real zero of a function is the x‐intercept(s) of the graph of the function.

so let us determine the value of x (zero of function) by setting y = 0.

$0=\frac{5}{2}x-5$

$\frac{5}{2}x-5=0$

$\frac{5}{2}x=5$

$5x=10$

$x=2$

Therefore, the zeros of the function will be:

x = 2

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3 years ago

You know how to play 21 songs on your guitar. (a) If you want to choose 8 of the songs to make a setlist to play for a small gat

UNO [17]

Answer:

(a) 8,204,716,800

(b) 5,985

Step-by-step explanation:

Combinations and Permutations

Combinatorics is the part of the discrete mathematics that studies the enumeration of groups or sorting of a determined number of elements. The concept of combinations is tied to the different forms to group elements where the order of their arrangements is not important or does not differentiate from the very same set of elements picked in a different order.

The concept of combinations is tied to the differents forms to group elements where the order of their arrangements is not important or does not differentiate from the very same set of elements picked in different order.

On the other hand, permutations or variations are sets selected in a specific order and another set with the same element but in different order is considered a different set.

If we have n elements available to pick from in sets of m elements each, there can be C(n,m) different combinations, and it's given by

$\displaystyle C(n,m)=\frac{n!}{m!(n-m)!}$