1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leona [35]
3 years ago
13

The cost function of a corn stand is C = 6n + 200, where n is the number of buckets of corn sold. The revenue function of this c

orn stand is r = 14n. Create a graph to show each of these functions. According to your graph, what is the break-even point for this corn stand?
A. n = 14
B. n = 6
C. n = 25
D. n = 28
Mathematics
2 answers:
guapka [62]3 years ago
6 0

Answer:

25

Step-by-step explanation:


Nikolay [14]3 years ago
3 0

Answer: Option 'C' is correct.

Step-by-step explanation:

Since we have given that

Cost function is defined as C = 6n+200

and Revenue function is defined as R = 14n

Since we need to find the break even point.

And we know that at break even point, C(x)= R(x).

6n+200=14n\\\\200=14n-6n\\\\200=8n\\\\n=\dfrac{200}{8}\\\\n=25

So, At n=25, there is the break even point for this corn stand.

Hence, Option 'C' is correct.

You might be interested in
What is m∠1 if m∠7 = 60°?
inna [77]

Step-by-step explanation:

95vxgr Tu fjvgzgvkvgshvysrvv

6 0
3 years ago
ANSWER THISS PLS! Need helpp
alex41 [277]
The answer would be rotation
8 0
3 years ago
(8.96 x 10^4) (7.97 x 10^9)/2.54 x10^6
viktelen [127]

\text{Scientific notation:}\\\\a\cdot10^k\\\\\text{where}\ 1\leq a

\dfrac{(8.96\cdot10^4)(7.97\cdot10^9)}{2.54\cdot10^6}=\dfrac{(8.96)(7.97)}{2.54}\cdot\dfrac{(10^4)(10^9)}{10^6}\\\\\text{Use}\ a^n\cdot a^m=a^{n+m}\ \text{and}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\dfrac{71.4112}{2.54}\cdot10^{4+9-6}=\dfrac{7141.12}{254}\cdot10^7\approx28.11\cdot10^7\\\\=2.811\cdot10\cdot10^7=2.811\cdot10^{7+1}\\\\=\boxed{2.811\cdot10^8}

6 0
3 years ago
Find all real and imaginary solutions to the equation.<br> x^3-2x^2+16x-32=0
777dan777 [17]

Answer:

The solution of x^3-2x^2+16x-32=0 is \mathbf{x=2,x=4i,x=-4i}

So, the real solutions is: x = 2

Imaginary solutions are : x = 4i, x = -4i

Step-by-step explanation:

We need to find real and imaginary solutions to the equations x^3-2x^2+16x-32=0

First of all we will make groups

(x^3-2x^2)(+16x-32)=0

Finding common terms from the groups

x^2(x-2)+16(x-2)=0\\(x-2)(x^2+16)=0

Now we know that if ab=0 then a=0 , b=0

x-2=0, x^2+16=0\\Simplifying:\\x=2, x^2=-16\\Taking\: square\: root\\x=2,\sqrt{x^2}=\sqrt{-16}\\x=2, x=\pm\sqrt{-16}\\x=2,x=\m\sqrt{-1}\sqrt{16}      \\We\:know\:\sqrt{-1}=i \:and \sqrt{x} \:\sqrt{16}=4 \\x=2,x=\pm4i\\x=2,x=4i,x=-4i

The solution of x^3-2x^2+16x-32=0 is \mathbf{x=2,x=4i,x=-4i}

So, the real solutions is: x = 2

Imaginary solutions are : x = 4i, x = -4i

3 0
3 years ago
A 1. Which 7 I . not equivalent to A -15 B a
Artyom0805 [142]
The answer is A because two negatives equal a positive
7 0
4 years ago
Other questions:
  • Find the center of the circle that you can circumscribe about ABC A=(-1,-2) B=(-5,-2) C=(-1,-7)
    12·1 answer
  • When solving -1/5(x-25) = 7, what is the correct sequence of operations?
    9·1 answer
  • LESS THAN 2 MINUTES HELP ME QUICK!!!
    6·1 answer
  • 24. Laisha paid for her and a friend to go to the movies. She
    15·1 answer
  • The school cafeteria sells 22 drinks every 10 minutes predict how many drinks the cafeteria would send during the 45 minutes lun
    15·2 answers
  • Two consecutive whole numbers that square root of 21 lies between
    5·1 answer
  • Zadanie 2c matematyka z plusem kl 8, (Oblicz długość boku rombu o przekątnych długości 10 i 6).
    6·2 answers
  • Yesterday 170 guests at a hotel called room service 255 gas did not call for room service what percentage of the guest at the ho
    7·1 answer
  • Nobody wants to answer my questions for brainliest <br> Do the boyz got me do?
    15·1 answer
  • Triangle A′B′C′ is the image of triangle ABC after a dilation.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!