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4 years ago

Can someone help me with this:

1 answer:

3 0

It does NOT disappear. Energy cannot be gained or destroyed, according to the Law of the Conservation of Energy. So, yes, we do get that energy back.

Hope this helps!

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Drake travel 1000m south and then 1200m west

olga2289 [7]

What's the question?

3 0

4 years ago

Consider the following list of numbers. 129, 685, 125, 511, 601, 52, 46 The height of a binary search tree is the maximum number

NemiM [27]

Answer:

The height of the tree is three (3) deep

Explanation:

It's 3 deep

Under 129, comes 125 and 685;

Under 125, comes 52 : Under 685, comes 511;

Under 52, comes 46 : Under 511, is 601.

This is illustrated below.

129

∧

125,685

|,|

52,511

|,|

46,601

5 0

4 years ago

Two children are riding on a merry-go-round that is rotating with a constant angular speed. Abbie is one meter from the center o

Ainat [17]

Answer:

Abbie’s acceleration is (1/2) Zak’s acceleration.

Explanation

1. Data:

a) ω = constant

b) Abbie: r₁ = 1 m

c) Zak: r₂ = 2 m

d) Ac₁ = ? Ac₂

2. Formulae

Ac = ω² r

3. Solution:

a) Abbie:

Ac₁ = ω² r₁ = ω² (1m)

b) Zack:

Ac₂ = ω² r₂ = ω² (2m)

c) Divide Ac₁ / Ac₂

Ac₁ / Ac₂ = ω² (1m) / [ω² (2m) ] = 1/2

⇒ Ac₁ = (1/2) Ac₂ = Ac₂ / 2 = 0.5 Ac₂

5 0

3 years ago

For a huge luxury liner to move with constant velocity, its engines need to supply a forward thrust of 7.45 105 N. What is the m

ehidna [41]

Answer:

7.45 10^5N.

Explanation:

according to newtons second law of motion;

$\sum F_x = ma_x\\F_{app} - F_r = ma_x$

Fapp is the applied force

Fr is the resistive force

m is the mass of the luxury

a is the acceleration

Since the huge luxury liner move with constant velocity, then acceleration is zero i.e a = 0. The equation becomes;

$F_{app} - F_f = m(0)\\F_{app} - F_f =0\\F_{app} = F_f$

This shows that the applied force will be equal to the resistive force if the velocity is constant.

Given Fr = 7.45 10^5 N therefore the resistive force will also be 7.45 10^5N.

Hence the magnitude of the resistive force exerted by the water on the cruise ship is 7.45 10^5N.

8 0

3 years ago

A flare is dropped from an airplane flying horizontally at uniform velocity (constant speed in a straight line). Neglecting air

jolli1 [7]

Answer:

Option B (remain vertically under the plane) is the correct option.

Explanation:

A flare would follow a particle trajectory with horizontal direction somewhat like airplane velocity as well as initial maximum motion as null but instead, gravity will induce acceleration. It would be lowered vertically underneath the plane before flare had already sunk to something like the surface.
There is no different movement in the airplane nor even the flash. And none of them can change its horizontal level.

Some other alternatives are given really aren't linked to the specified scenario. So choice B is the perfect solution to that.

7 0

3 years ago