We have that for the Question "In the same year, the average finishing <em>time</em> for U.S. women was 4 <u>hours </u>and 41 <em>minutes</em>. What was the average female speed in miles per <em>hour</em>?" it can be said that
The average female speed in miles per hour
From the question we are told
In the same year, the <u>average</u> finishing <em>time</em> for U.S. women was 4 <u>hours </u>and 41 <em>minutes</em>. What was the average female speed in <u>miles</u> per <em>hour</em>?
<h3>Average speed </h3>
This is defined as the collective <u>mean</u> of different travel <em>intervals </em>
Generally the equation for Speed is mathematically given as
V=\frac{Distance}{Time}
Therefore
For 4 <u>hours </u>and 41 <em>minutes=4.683hours</em>
This travels time was <em>obtained </em>over a series of distance
<em>Hence</em>
<em>Distance D</em>
The average female <em>speed</em> in miles per hour
For more information on speed visit
brainly.com/question/7359669
Answer:
The bomb will remain in air for <u>17.5 s</u> before hitting the ground.
Explanation:
Given:
Initial vertical height is,
Initial horizontal velocity is,
Initial vertical velocity is,
Let the time taken by the bomb to reach the ground be 't'.
So, consider the equation of motion of the bomb in the vertical direction.
The displacement of the bomb vertically is
Acceleration in the vertical direction is due to gravity,
Therefore, the displacement of the bomb is given as:
So, the bomb will remain in air for 17.5 s before hitting the ground.
Answer:
Explanation:
Answer: Let ke = 1/2 IW^2 = 1/2 kMr^2 W^2 be Earth's rotational KE. W = 2pi/24 radians per hour rotation speed and k = 2/5 for a solid sphere M is Earth mass, r = 6.4E6 m.
Then ke = 1/2 2/5 6E24 (6.4E6)^2 (2pi/(24*3600))^2 = ? Joules. You can do the math, note W is converted to radians per second for unit consistency.
Let KE = 1/2 KMR^2 w^2 be Earth's orbital KE. w = 2pi/(365*24) radians per hour K = 1 for a point mass. Note I used 365 days, a more precise number is 365.25 days per year, which is why we have Leap Years.
Find KE/ke = 1/2 KMR^2 w^2//1/2 kMr^2 W^2 = (K/k)(w/W)^2 (R/r)^2 = (5/2) (365)^2 (1.5E11/6.4E6)^2 = 7.81E9 ANS
Answer:
The Height of a pyramid is 4r.
Explanation:
Explanation is in the following attachments