Answer:
336 ways ;
56 ways
Step-by-step explanation:
Number of ways to have the officers :
Number of qualified candidates, n = 8
Number of officer positions to be filled = 3
A.)
Using permutation (since the ordering matters):
nPr = n! ÷(n-r)!
8P3 = 8! ÷ (8-3)!
8P3 = 8! ÷ 5!
8P3 = (8*7*6)
8P3 = 336 ways
B.) Different ways of appointing committee: (ordering doesn't count as officers can also be appointed)
Using the combination relation :
nPr = n! ÷(n-r)!r!
8C3 = 8! ÷ (8-3)! 3!
8C3 = 8! ÷ 5!3!
8C3 = (8*7*6) ÷ (3*2*1)
8C3 = 336 / 6
8C3 = 56 ways
2/3 of 18...." of " means multiply
2/3 * 18 = 36/3 = 12....she has memorized 12 words so far
Answer:f(3)=26,f(6)=215
Step-by-step explanation:
f(x)=3^x-1
f(3)=3^3-1
f(3)=3x3x3-1
f(3)=27-1
f(3)=26
f(6)=6^3-1
f(6)=6x6x6-1
f(6)=216-1
f(6)=215
Availability of first truck probability P (1) = 0.74
Availability of second truck probability P (2) = 0.57
Availability of both truck probability P (1 and 2) = 0.46
So the probability of at least one available P (1 or 2) = P (1) + P (2) - P (1 and 2) = 0.74 + 0.57 - 0.46 = 0.85
Now the probability of at neither available = 1 - P (1 or 2) = 1 – 0.85 = 0.15
