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hjlf
3 years ago
7

Niko wants to buy a bicycle that costs $145. He has already saved $25. He says that he can determine the amount he still needs t

o save by using
the equation b– 25 = 145. Determine the error in Niko’s thinking and write the correct equation that Niko can use to determine how much he still needs to save.

Please help me with this!
Mathematics
2 answers:
nevsk [136]3 years ago
4 0
145 - 25 = b
b = 120
dybincka [34]3 years ago
3 0

Answer:

He is incorrect because if you're going to find out how much he needs, you need to subtract the total by what he already has. So, the answer will be

145-25=b. (but if you want to know the answer to b, it's 145-25=120, so he needs to save up 120 more dollars.) Let me know if this helped!! Good luck.

Step-by-step explanation:

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Answer:

the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

Step-by-step explanation:

Given the data in the question;

we know that a type 11 error occur when a null hypothesis is false and we fail to reject it.

as in it in the question;

obtained mean is 9.8 which is obviously not equal to 8.3

But still we fail to reject the null hypothesis says mean is 8.3

Hence we have to find the probability of type 11 error

given that; it is right tailed and o.5, it corresponds to 1.645

so

z is equal to 1.645

z = (x-μ)/\frac{S}{\sqrt{n} }

where our standard deviation s = 3.8

sample size n = 50

mean μ = 8.3

we substitute

1.645 = (x - 8.3)/\frac{3.8}{\sqrt{50} }

1.645 = (x - 8.3) / 0.5374

0.884023 = x - 8.3

x = 0.884023 + 8.3

x = 9.18402

so, by general rule we will fail to reject the null hypothesis when we will get the z value less than 1.645

As we reject the null hypothesis for right tailed test when the obtained test statistics is greater than the critical value

so, we will fail to reject the null hypothesis as long as we get the sample mean less than 9.18402

Now, for mean 9.8 and standard deviation 3.8 and sample size 50

Z =  (9.18402 - 9.8)/\frac{3.8}{\sqrt{50} }

Z = -0.61598 / 0.5374

Z = - 1.1462 ≈ - 1.15

from the z-score table;

P(z<-1.15) = 0.1251

Therefore, the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

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