Question

H(n) = n^2 - 4n; Find h(-3)

Answer 1

For this case we have the following function:

$h (n) = n ^ 2-4n$

We must find the value of the function when $n = -3$.

Substituting we have:

$h (-3) = (- 3) ^ 2-4 (-3)$

We must bear in mind that the law of multiplication signs complies:

$- * - = +$

So:

$h (-3) = 9 + 12\\h (-3) = 21$

Answer:

$h (-3) = 21$

Answer 2

Answer:

h(-3)= (-3)^2 - 4(-3)

9+12= 21