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2 years ago

H(n) = n^2 - 4n; Find h(-3)

Mathematics

2 answers:

k0ka [10]2 years ago

7 0

For this case we have the following function:

$h (n) = n ^ 2-4n$

We must find the value of the function when $n = -3$ .

Substituting we have:

$h (-3) = (- 3) ^ 2-4 (-3)$

We must bear in mind that the law of multiplication signs complies:

$- * - = +$

So:

$h (-3) = 9 + 12\\h (-3) = 21$

Answer:

$h (-3) = 21$

Vladimir79 [104]2 years ago

3 0

Answer:

h(-3)= (-3)^2 - 4(-3)

9+12= 21

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Answer:

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2 years ago

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Answer : value of x and y in the matrix equation is:

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Step-by-step explanation :

The matrix expression is:

$\left[\begin{array}{ccc}x+4\\y^2+1\end{array}\right]+\left[\begin{array}{ccc}-9x\\-17\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]$

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Now we have to equating left hand side matrix to right hand matrix, we get:

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natta225 [31]

ANSWER
$=\frac{19}{17} \pi$

EXPLANATION

To find a positive angle that is coterminal with
$- \frac{15}{17} \pi$

We add multiples of 2π until we get a positive angle that is less than one revolution,

We add to obtain,

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This simplifies to,

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