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2 years ago

The sides of a triangle 17, 3 and 15. Determine the triangle is a right triangle

Mathematics

1 answer:

Sloan [31]2 years ago

6 0

Answer: No.

Step-by-step explanation: This is not a right triangle because if you add up all the sides, it does not equal 90 degrees.

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14) The number of students at LAMS is 1872 students. The ratio of girls to

bogdanovich [222]

Answer:

310

Step-by-step explanation:

total no.of students=1872

ratio of boys to girls=7:5

sum of ratio=total of students

12/12=1872

7/12=?

7/12*1872/1=1092which is the number of girls

1872-1092=780which is the number of boys

difference =1092-780= 310

7 0

2 years ago

The town of Haverford just bought land to make a new park. The land is in the shape of a rectangle that is 2/3 of a mile wide an

frosja888 [35]

Answer:

Step-by-step explanation:

6 0

2 years ago

Pavel, Ruth and Josh have part-time jobs.

MrMuchimi

M+m+z/3=3m
m+m+z=9m
2m+z=9m
z=7m
m+m+7m/3=3m
9m=9m
m=1
1+1+z/3=3
2+z=9
z=7
idk but i think that one person gets paid 7 dollars and the other ppl get paid 1 dollar----- this is probably veryyyyy wrong

8 0

2 years ago

A local merchandized car wash can clean 51 vehicles in 1.5 hours. At this rate how many vehicles can the car wash clean in 12 ho

Marianna [84]

Answer:

408 Cars

Step-by-step explanation:

Dividing 12 Hours by 1.5 hour

= 12/1.5 = 8

Now Multiplying 8 by 51

=51 x 8

= 408 cars

7 0

2 years ago

Let y(t) be the solution to y˙=3te−y satisfying y(0)=3 . (a) Use Euler's Method with time step h=0.2 to approximate y(0.2),y(0.4

OLEGan [10]

Answer:

$y(0.2)=3$ , $y(0.4)=3.005974448$ , $y(0.6)=3.017852169$ , $y(0.8)=3.035458382$ , and $y(1.0)=3.058523645$

The general solution is $y=\ln \left(\frac{3t^2}{2}+e^3\right)$

The error in the approximations to y(0.2), y(0.6), and y(1):

$|y(0.2)-y_{1}|=0.002982771$

$|y(0.6)-y_{3}|=0.008677796$

$|y(1)-y_{5}|=0.013499859$

Step-by-step explanation:

Point a:

The Euler's method states that:

$y_{n+1}=y_n+h \cdot f \left(t_n, y_n \right)$ where $t_{n+1}=t_n + h$

We have that $h=0.2$ , $t_{0}=0$ , $y_{0} =3$ , $f(t,y)=3te^{-y}$

We need to find $y(0.2)$ for $y'=3te^{-y}$ , when $y(0)=3$ , $h=0.2$ using the Euler's method.

So you need to:

$t_{1}=t_{0}+h=0+0.2=0.2$

$y\left(t_{1}\right)=y\left(0.2)=y_{1}=y_{0}+h \cdot f \left(t_{0}, y_{0} \right)=3+h \cdot f \left(0, 3 \right)=$

$=3 + 0.2 \cdot \left(0 \right)= 3$

$y(0.2)=3$

We need to find $y(0.4)$ for $y'=3te^{-y}$ , when $y(0)=3$ , $h=0.2$ using the Euler's method.

So you need to:

$t_{2}=t_{1}+h=0.2+0.2=0.4$

$y\left(t_{2}\right)=y\left(0.4)=y_{2}=y_{1}+h \cdot f \left(t_{1}, y_{1} \right)=3+h \cdot f \left(0.2, 3 \right)=$

$=3 + 0.2 \cdot \left(0.02987224102)= 3.005974448$

$y(0.4)=3.005974448$

The Euler's Method is detailed in the following table.

Point b:

To find the general solution of $y'=3te^{-y}$ you need to:

Rewrite in the form of a first order separable ODE:

$e^yy'\:=3t\\e^y\cdot \frac{dy}{dt} =3t\\e^y \:dy\:=3t\:dt$

Integrate each side:

$\int \:e^ydy=e^y+C$

$\int \:3t\:dt=\frac{3t^2}{2}+C$

$e^y+C=\frac{3t^2}{2}+C\\e^y=\frac{3t^2}{2}+C_{1}$

We know the initial condition y(0) = 3, we are going to use it to find the value of $C_{1}$

$e^3=\frac{3\left(0\right)^2}{2}+C_1\\C_1=e^3$

So we have:

$e^y=\frac{3t^2}{2}+e^3$

Solving for y we get:

$\ln \left(e^y\right)=\ln \left(\frac{3t^2}{2}+e^3\right)\\y\ln \left(e\right)=\ln \left(\frac{3t^2}{2}+e^3\right)\\y=\ln \left(\frac{3t^2}{2}+e^3\right)$