Find the area of a circle with a radius of 1.5 cm

Mathematics

2 answers:

viktelen [127]3 years ago

3 0

The answer would be 7.07 if you are using the whole pi

Yuki888 [10]3 years ago

3 0

Area = pi * radius^2

A = 3.14 * 1.5^2

A = 7.07 square centimeters

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36 out of 100 randomly selected taxpayers knew about tax incentives for installing energy-saving furnaces. Find a 90% confidence

tresset_1 [31]

Answer:

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 100, \pi = \frac{36}{60} = 0.6$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 - 1.645\sqrt{\frac{0.36*0.64}{100}} = 0.28$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 + 1.645\sqrt{\frac{0.36*0.64}{100}} = 0.44$

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).

7 0

3 years ago

Number of Students

erma4kov [3.2K]

Answer: 15
Step-step-explanation:

4 0

3 years ago

Give the equation of the horizontal asymptote shown below.

Oxana [17]

Polynomial division yields

$\dfrac{7x^2}{x^2+5}=7-\dfrac{35}{x^2+5}$

As $x\to\pm\infty$ , you have the remainder term approaching $0$ , so the horizontal asymptote is the line $y=7$ .