Using the Hardy-Weinberg equations, the percentage of carriers of cystic fibrosis is 8.19%.
<h3>What are the Hardy-Weinberg equations?</h3>
The Hardy-Weinberg equations describe the relationship between alleles in a population that is fairly constant.
The Hardy-Weinberg equations are given below as;

Hardy-Weinberg equations
Percentage of carriers = 2pq
Percentage of carriers = 2 * 0.09 * 0.91 * 100 = 8.19%
Therefore, the percentage of carriers of cystic fibrosis is 8.19%.
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Answer:
I'm a eukaryotic, plant cell. I would be the central vacuole that stores excess water, food, and waste. There's only one of me in a plant cell. If I weren't in the cell, it would collapse or burst, because it well lose its turgor pressure. Moreover, the cell won't have enough space to store all the water and molecules needed for conducting photosynthesis. I resemble the stomach in a human body; a stomach stores food and water for later use.
The AB blood type has both A and B alleles.This illustrates principle of co-dominance