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nydimaria [60]
3 years ago
7

Algebra Question - 24=3r

Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0
Compute 24/3=r

then r is equal to 12
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In which quadrant of the coordinate graph does point J lie?
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thats quadrant 2

Step-by-step explanation:

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3 years ago
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Consider that the length of rectangle A is 10 cm and its width is 6 cm. Which rectangle is similar to rectangle A? A) A rectangl
HACTEHA [7]
ANSWER

B) A rectangle with a length of 15 cm and a width of 9 cm.

EXPLANATION

The given rectangle, A, has length, 10cm and its width is 6cm.

The rectangle that is similar to rectangle A, has the corresponding sides in the same proportion.

For option A, the triangle has length 9cm and width 6cm.

The ratio of the corresponding sides are:

\frac{10}{9} \ne \frac{6}{6}

Since the ratios are not equal, the two triangles are not similar.

For the triangle in option B, the length is 15cm and the width is 9cm.

The ratio of the corresponding sides are:

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Since the sides of the triangle are in the same proportion, the two triangles are similar.

For option C, the proportions are not the same.

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8 0
3 years ago
Use Newton's method with initial approximation x1 = −2 to find x2, the second approximation to the root of the equation x3 + x +
nevsk [136]

Answer:

x_2 \approx -1.769

Step-by-step explanation:

Let f(x)=x^3+x+7

So f'(x)=3x^2+1

x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}

Let x_1=-2

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So we are evaluating -2-\frac{f(-2)}{f'(-2)}

First step find f(-2)

Second step find f'(-2)

Third step plug in those values and apply PEMDAS!

f(-2)=(-2)^3+(-2)+7=-8-2+7=-10+7=-3

f'(-2)=3(-2)^2+1=3(4)+1=12+1=13

So

x_2=-2-\frac{-3}{13} \\\\ x_2=\frac{-26+3}{13} \\\\ x_2=\frac{-23}{13} \\\\ x_2 \approx -1.769

5 0
3 years ago
What is the value of b?
labwork [276]
The value of b is 61°.

you solve by doing this:
add up the two given angles, 58° and 61° to get 119°. then you subtract from 180° to get 61.
4 0
3 years ago
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