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3 years ago

5

There are four aces from a deck of cards. If a coin is tossed in an ace is chosen, what is the probability of getting heads on t

he coin and an ace of hearts?

1 answer:

harina [27]3 years ago

6 0

Answer:

1/8

Step-by-step explanation:

coin toss is 1/2, probability of getting an ace of hearts is 1/4

therefore 1/2 x 1/4 = 1/8

You might be interested in

A one-parameter family of solutions of the de p' = p(1 − p) is given below.

tensa zangetsu [6.8K]

Answer:

A solution curve pass through the point (0,4) when $c_{1} = -\frac{4}{3}$ .

There is not a solution curve passing through the point(0,1).

Step-by-step explanation:

We have the following solution:

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

Does any solution curve pass through the point (0, 4)?

We have to see if P = 4 when t = 0.

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

$4 = \frac{c_{1}}{1 + c_{1}}$

$4 + 4c_{1} = c_{1}$

$c_{1} = -\frac{4}{3}$

A solution curve pass through the point (0,4) when $c_{1} = -\frac{4}{3}$ .

Through the point (0, 1)?

Same thing as above

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

$1 = \frac{c_{1}}{1 + c_{1}}$

$1 + c_{1} = c_{1}$

$0c_{1} = 1$

No solution.

So there is not a solution curve passing through the point(0,1).

3 0

3 years ago

Wich is the result of 23*1/5?

aleksklad [387]

Answer:

The answer is $\frac{23}{5}$ or $4.6$ .

Step-by-step explanation:

Solve the following equation:

$23 \times \frac{1}{5}$

-Multiply $23$ and $\frac{1}{5}$ to get

$23 \times \frac{1}{5} = \frac{23}{5} = 4.6$

So, now you have found the answer.

8 0

3 years ago

Read 2 more answers

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0

3 years ago

Five thousand tickets are sold at $1 each for a charity raffle. Tickets are to be drawn at random and monetary prizes awarded a

aksik [14]

Answer:

the expected value of this raffle if you buy 1 ticket = -0.65

Step-by-step explanation:

Given that :

Five thousand tickets are sold at $1 each for a charity raffle

Tickets are to be drawn at random and monetary prizes awarded as follows: 1 prize of $500, 3 prizes of $300, 5 prizes of $50, and 20 prizes of $5.

Thus; the amount and the corresponding probability can be computed as:

Amount Probability

$500 -$1 = $499 1/5000

$300 -$1 = $299 3/5000

$50 - $1 = $49 5/5000

$5 - $1 = $4 20/5000

-$1 1- 29/5000 = 4971/5000

The expected value of the raffle if 1 ticket is being bought is as follows:

$E(x) = \sum x * P(x)$

$E(x) = (499 * \dfrac{1}{5000} + 299 *\dfrac{3}{5000} + 49 *\dfrac{5}{5000} + 4 * \dfrac{20}{5000} + (-1 * \dfrac{4971}{5000} ))$

$E(x) = (0.0998 + 0.1794+0.049 + 0.016 + (-0.9942 ))$

$E(x) = (0.3442 -0.9942 )$

$\mathbf{E(x) = -0.65}$

Thus; the expected value of this raffle if you buy 1 ticket = -0.65

7 0

3 years ago

PLS HURRY AND HELP ME Larry buys peanut butter and bananas at the grocery store. He spends $3.89 on peanut butter and $9.38 in a

Tamiku [17]

Answer:

x = $5.49 cost of the bananas

Step-by-step explanation:

x = cost of the bananas

$3.89 = cost of the peanut butter

$ 9.38 is the cost of both

Bananas + peanut butter = $9.38

x + $3.89 = $9.38

<u> - $ 3.89 = -$3.89 </u> Subtract $3.89 from both sides

x = $5.49

5 0

3 years ago