<h3>I’ll teach you solve 3x^-2 and 5x^2y(2x^4y^-3)</h3>
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(A)
3x^-2
Apply exponent rule:
3*1/x^2
Multiply fractions:
1*3/x^2
Multiply the numbers:
1*3= 3
3/x^2
Your Answer Is
(B)
5x^2y(2x^4 y^-3)
Apply exponent rule:
5y*2x^2+4 y^-3
Add the numbers:
2+4= 6
5y*2x^6 y^-3
Apply exponent rule:
5*2x^6 y^1-3
Subtract the numbers:
1-3= -2
5*2x^6 y^-2
Apply exponent rule:
5*2* 1/y^2 x^6
Multiply fractions:
1*5*2x^6/y^2
Multiply the numbers:
1*5*2= 10
10x^6/y^2
Your Answer Is
Plz mark me as brainliest if this helped :)
