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spayn [35]
3 years ago
7

What is the verbal sentence for x^2 -9=27

Mathematics
1 answer:
Ratling [72]3 years ago
8 0
X^2 - 9 = 27

the square of a number x decreased by 9 is 27
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5. Using only odd numbers for numerators,
Lady bird [3.3K]

Answer:

  • 3/4 - 1/4 = 1/2
  • 5/8 - 1/8 = 1/2

Step-by-step explanation:

You can pick just about any fraction with an odd numerator and find another at distance 1/2 from it.

For example, 5/7 - 1/2 = 10/14 - 7/14 = 3/14. So your subtraction problem can be ...

  5/7 - 3/14 = 1/2

Choosing a denominator divisible by 4 can make both parts of the problem use the same denominator.

  3/4 - 2/4 = 1/4, so the corresponding subtraction problem is 3/4 - 1/4 = 1/2.

  5/8 - 4/8 = 1/8, so the subtraction problem is 5/8 -1/8 = 1/2.

4 0
3 years ago
Nadia cuts 3 pieces of equal length from 8 yards of ribbon .How is each piece
Volgvan
Your answer is 2.66666667
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3 years ago
What is the quotient of 8592÷24?​
frez [133]

Answer:

358

Step-by-step explanation:

6 0
3 years ago
Simplify.<br> Rewrite the expression in the form b^n<br><br> (b^3)^2
Alexxandr [17]

Step-by-step explanation:

a^n={\underbrace{a\cdot a\cdot a\cdot...\cdot a}_{n}

<h2>METHOD 1.</h2>

\left(b^3\right)^2=\underbrace{b^3\cdot b^3}_{2}=\underbrace{b\cdot b\cdot b}_{3}\cdot\underbrace{b\cdot b\cdot b}_{3}=\underbrace{b\cdot b\cdot b\cdot b\cdot b\cdot b}_{6}=b^6

<h2>METHOD 2.</h2>

\left(b^3\right)^2=\underbrace{b^3\cdot b^3}_{2}=b^{3+3}=b^6\qquad\text{used}\ a^n\cdot a^m=a^{n+m}

<h2>METHOD 3.</h2>

\left(b^3\right)^2=\left(\underbrace{b\cdot b\cdot b}_{3}\right)^2=b^2\cdot b^2\cdot b^2=b^{2+2+2}=b^6\\\text{used}\ (ab)^n=a^nb^n,\ a^n\cdot a^m=a^{n+m}

<h2>METHOD 4.</h2>

\left(b^3\right)^2=b^{3\cdot2}=b^6\qquad\text{used}\ \left(a^n\right)^m=a^{nm}

5 0
3 years ago
Evaluate the expression when m=4<br> m^2-9m-5
enyata [817]

Answer:-25

Step-by-step explanation:

simplify

3 0
3 years ago
Read 2 more answers
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