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3 years ago

What is the verbal sentence for x^2 -9=27

Mathematics

1 answer:

Ratling [72]3 years ago

8 0

X^2 - 9 = 27

the square of a number x decreased by 9 is 27

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What is the greatest common factor for 12&15

murzikaleks [220]

The greatest common factor of 12 and 15 is 3 because it is the greatest number divisible by both 12 and 15.

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3 years ago

Ellie drives 22.5 miles in 45 minutes. If she drove three hours in total at the same rate, how far did she go?

Scilla [17]

Answer:

Ellie drove 90 miles in three hours.

Step-by-step explanation:

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2 years ago

Find the domain and range with a vertex of (1,-2)

klemol [59]

Answer:

see explanation

Step-by-step explanation:

the domain ( values of x ) that a quadratic can have is all real numbers

domain : - ∞ < x < ∞

the range ( values of y ) are from the vertex upwards , that is

range : y ≥ - 2

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2 years ago

Simplify the expression below.

Novay_Z [31]

Answer:

$\displaystyle 6$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{7^2 - 13}{24 - 18}$

Step 2: Evaluate

[Fraction] Exponents: $\displaystyle \frac{49 - 13}{24 - 18}$
[Fraction] Subtract: $\displaystyle \frac{36}{6}$
[Fraction] Divide: $\displaystyle 6$

5 0

2 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

3 years ago