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4 years ago

if the player hits the ball from point A, where should s/he aim the ball so that the ball goes in the hole?

Mathematics

1 answer:

Nataly_w [17]4 years ago

4 0

The ball should be aimed to the point of the wall that is about 45 degrees from the wall.

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How do I solve this problem step by step?

Rom4ik [11]

Answer:

V = 3

Step-by-step explanation:

Given:

Perimeter of the pentagon is 52 units.

Solve for value of v.

Solve:

Let first put it into a equation base on the given;

6v + 8 + 8 + 3v + 1 + v + 5 = 52

Add the numbers

6v + 22 + 3v + v = 52

Combine like terms

10v + 22 = 52

Subtract 22 from both sides

10v + 22 - 22 = 52 - 22

Simplify

10v = 30

Divide both sides by 10

10v/10 = 30/10

Simplify

v = 3

Check Answer:

6(3) + 8 + 8 + 3(3) + 1 + (3) + 5

18 + 8 + 8 + 3(3) + 1 + (3) + 5

18 + 16 + 9 + 1 + 8

18 + 16 + 9 + 9

18 + 16 + 18

36 + 16

52

Hence, v = 3

For more information:

brainly.com/question/18640399

Kavinsky

6 0

2 years ago

Read 2 more answers

Two students in your class, Tucker and Karly, are disputing a function. Tucker says that for the function, between x = –3 and x

Effectus [21]

The difference between Tucker and Karly's take is that Tucker's solution is analytical while Karly's is graphical. But both are correct either way.

For Tucker's solution, let's say at x=-3 the value for y is 4, and at x=3, the value of y is still 4, then the average rate of change or slope is 0. Note that the slope of the curve is Δy/Δx. Since there is no change for Δy, the slope is zero.

For Karly's solution, even if the curve travels high or low but would have the same elevation of x=-3 and x=3, the average rate of change is still zero. It is actually just same with Tucker's but Karly just verbalizes her solution that was observed visually.

7 0

3 years ago

X2 - 6x + 12 and y = 2x - 4, algebraically are

olga_2 [115]

The solution is (4, 4)

Solution:

Given system of equations are:

$y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2$

Substitute eqn 2 in eqn 1

$x^2 - 6x + 12 = 2x - 4$

Make the right side of equation 0

$x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0$

Solve by quadratic equation

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4$

Substitute x = 4 in eqn 2

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0

3 years ago

Anyone know how to do this? Please help

denpristay [2]

Answer:

93.6 inch^2

Step-by-step explanation:

sides=6 side-length=6 inches Apothem= 5.2 inches Area= 6*(1/2)(6)(5.2)

3 0

3 years ago

the sum of two numbers is 61. five times the smaller number is 23 more than the larger. find the numbers

Stella [2.4K]

Smaller Number = X
5x - 23 = Larger Number

X + (5x - 23) = 61
6x - 23 = 61
6x = 84
X = 14

6 0

3 years ago