Question

It takes 20 hours and $400 to interview a candidate, and it takes 120 hours and $3600 to train an employee. A company has less than $95000 to interview and train employees, and it wants to spend at most 470 hours to do so. Let C denote the number of candidates they interview and E the number of employees they train.

Answer 1

Let C denote the number of candidates they interview and E the number of employees they train.

If it takes 20 hours and $400 to interview a candidate, then it takes 20C hours and $400C to interview C candidates.

If it takes 120 hours and $3600 to train an employee, then it takes 120E hours and $3600E to train E employees.

Company has less than $95000, then 400C+3600E<95000.

Company wants to spend at most 470 hours, then $20C+120E\le 470$.

You obtain the system of two inequalities:


$\left \{ {{400C+3600E\ \textless \ 95000} \atop {20C+120E\le 470}} \right. \\ \left \{ {{4C+36E\ \textless \ 950} \atop {C+6E\le 23.5}} \right. \\ \left \{ {{4C+36E\ \textless \ 950} \atop {4C+24E\le 94}} \right.$
Then you can solve this system according to your demands.