Answer: hypotenuse = 
Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (
) of the right triangle, .i.e.:

In this question:
= 
2bc
Substituing and taking square root to find hypotenuse:

Calculating:


=
, then:


Hypotenuse for the right-angled triangle is
units
Pemdas
parenthasees exponents mult/division additon/subtraction
parethenasees
x-3 and x+5 we can't do anything with so next
5(x-3)=5x-15
2(x+5)=2x+10
5x-15+2=5x-13
(2x+10-9)=2x+1
(5x-13)-3(2x+1)
-3(2x+1)=-6x-3
5x-13-6x-3=-x-16
4(-x-16)=-4x-64
the answer is -4x-64
Answer:

Step-by-step explanation:
![\sf{ [ (4 \frac{1}{6} + 2 \frac{1}{3} ) \div 4 \frac{1}{3}] - 1\frac{1}{2} }](https://tex.z-dn.net/?f=%20%5Csf%7B%20%5B%20%284%20%5Cfrac%7B1%7D%7B6%7D%20%20%2B%202%20%5Cfrac%7B1%7D%7B3%7D%20%29%20%20%5Cdiv%204%20%5Cfrac%7B1%7D%7B3%7D%5D%20-%20%201%5Cfrac%7B1%7D%7B2%7D%20%7D)
Convert the mixed numbers into improper fraction
![\longrightarrow{ \sf{ [ ( \frac{25}{6} + \frac{7}{3} ) \div \frac{13}{3}] - \frac{3}{2}}}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5B%20%28%20%5Cfrac%7B25%7D%7B6%7D%20%20%2B%20%20%5Cfrac%7B7%7D%7B3%7D%20%29%20%5Cdiv%20%20%5Cfrac%7B13%7D%7B3%7D%5D%20-%20%20%5Cfrac%7B3%7D%7B2%7D%7D%7D%20)
Add the fractions : 25 / 6 and 7 / 3
While performing addition or subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fraction.
To do so, first take the L.C.M of 6 and 3 which results to 6
![\longrightarrow\sf{ [( \frac{25 + 7 \times 2}{6} ) \div \frac{13}{3} ] - \frac{3}{2}}](https://tex.z-dn.net/?f=%20%20%5Clongrightarrow%5Csf%7B%20%5B%28%20%5Cfrac%7B25%20%2B%207%20%5Ctimes%202%7D%7B6%7D%20%29%20%5Cdiv%20%20%5Cfrac%7B13%7D%7B3%7D%20%5D%20-%20%20%5Cfrac%7B3%7D%7B2%7D%7D%20)
![\longrightarrow{ \sf{ [( \frac{25 + 14}{6} ) \div \frac{13}{3} ] - \frac{3}{2} }}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5B%28%20%5Cfrac%7B25%20%2B%2014%7D%7B6%7D%20%29%20%20%5Cdiv%20%20%5Cfrac%7B13%7D%7B3%7D%20%20%5D%20-%20%20%5Cfrac%7B3%7D%7B2%7D%20%7D%7D)
![\longrightarrow{ \sf{ [ \frac{39}{6} \div \frac{13}{3}] - \frac{3}{2} }}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5B%20%5Cfrac%7B39%7D%7B6%7D%20%20%5Cdiv%20%20%5Cfrac%7B13%7D%7B3%7D%5D%20-%20%20%5Cfrac%7B3%7D%7B2%7D%20%7D%7D)
Multiply the dividend by the reciprocal of the divisor.
Reciprocal of any number or fraction can be obtained by interchanging the position of numerator and denominator
![\longrightarrow{ \sf{ [ \frac{39}{6} \times \frac{3}{13} ] - \frac{3}{2}}}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5B%20%20%5Cfrac%7B39%7D%7B6%7D%20%20%5Ctimes%20%20%5Cfrac%7B3%7D%7B13%7D%20%5D%20-%20%20%5Cfrac%7B3%7D%7B2%7D%7D%7D%20)
To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term
![\longrightarrow{ \sf{ [ \frac{39 \times 3}{6 \times 13} ] - \frac{3}{2}}}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5B%20%20%5Cfrac%7B39%20%5Ctimes%203%7D%7B6%20%5Ctimes%2013%7D%20%5D%20-%20%20%5Cfrac%7B3%7D%7B2%7D%7D%7D%20)
![\longrightarrow{ \sf{ [ \frac{117}{78} ] - \frac{3}{2} }}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5B%20%20%5Cfrac%7B117%7D%7B78%7D%20%20%5D%20-%20%20%5Cfrac%7B3%7D%7B2%7D%20%7D%7D)

While performing the addition or subtraction of like fractions , you just have to add or subtract the numerator respectively in which the denominator is retained same

Subtract 3 from 3

Divide 0 by 2

Hope I helped!
Best regards!
Answer:
G: (-2, 0.5)
Step-by-step explanation:
the "X" is -2 and then the "Y" is 0.5 because it is between 0 and 1, so we could the that Y-axis is being added by 0.5 each time.
The number 2.71828182846... is irrational since the decimal portion "71828182846" goes on forever without any pattern. We cannot write this as a fraction or ratio of whole numbers.