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3 years ago

Gina Wilson All Things Algebra 2015, Unit 11

Mathematics

2 answers:

sertanlavr [38]3 years ago

7 0

Answer:

What are we answering?? theres nothing there

Step-by-step explanation:

galben [10]3 years ago

5 0

Answer:

uhh there's nothing-

Step-by-step explanation:

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Ashley is taking a road trip to visit her friend. She drives 87.5 miles before taking a break

DanielleElmas [232]

Answer:

112.5

Step-by-step explanation:

200 - 87.5 = 112.5

6 0

2 years ago

Can you answer this pls

Gnoma [55]

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3 years ago

Write an inequality that represents the verbal expression below.

just olya [345]

Answer:

-3t > 11

Step-by-step explanation:

hope this helps :)

7 0

3 years ago

Solve the given differential equation by using an appropriate substitution. The DE is a Bernoulli equation.

Mama L [17]

Multiplying both sides by $y^2$ gives

$xy^2\dfrac{\mathrm dy}{\mathrm dx}+y^3=1$

so that substituting $v=y^3$ and hence $\frac{\mathrm dv}{\mathrm dv}=3y^2\frac{\mathrm dy}{\mathrm dx}$ gives the linear ODE,

$\dfrac x3\dfrac{\mathrm dv}{\mathrm dx}+v=1$

Now multiply both sides by $3x^2$ to get

$x^3\dfrac{\mathrm dv}{\mathrm dx}+3x^2v=3x^2$

so that the left side condenses into the derivative of a product.

$\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2$

Integrate both sides, then solve for $v$ , then for $y$ :

$x^3v=\displaystyle\int3x^2\,\mathrm dx$

$x^3v=x^3+C$

$v=1+\dfrac C{x^3}$

$y^3=1+\dfrac C{x^3}$

$\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}$

6 0

3 years ago

Please helpppppppppppp

morpeh [17]

Answer:

7.7 km

Explanation:

Use cosine rule as here given two sides and one angle.

Cosine rule states:

a² = b² + c² - 2bc cos(A)

While solving, treat a = 7.5 km as to that opposite angle is given of 68°

then b = missing side, c = 5.2 km, A = 68°

Applying rule:

7.5² = b² + 5.2² - 2(b)(5.2) cos(68)

56.25 = b² + 27.04 - 3.8959b

56.25 - 27.04 = b² - 3.8959b

b² - 3.8959b = 29.21

b² - 3.8959b - 29.21 = 0

apply quadratic equation, Here [a = 1, b = - 3.8959, c = -29.21]

$\sf b = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \quad\:when \:\ ax^2 + bx + c = 0$

$\sf b = \dfrac{ -(-3.8959) \pm \sqrt{(-3.8959)^2 - 4(1)(-29.21)}}{2(1)}$

$\sf b = 7.69 291 \quad or \quad b = -3.797$

$\sf b = 7.7 \quad (rounded \ to \ nearest \ tenth)$

As length cannot be negative. Hence the value of b is only 7.7 km

7 0

2 years ago

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