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Otrada [13]
3 years ago
7

A recipe calls for 3 quarts of water, How many fl. oz. is this ?

Mathematics
2 answers:
adell [148]3 years ago
7 0

3 quarts of water is a total of 96 fluid ounces. Hope this helps! :)

<h2>-CloutAnswers</h2>
Karolina [17]3 years ago
6 0

i belive there is 96 fluid ounces in 3 quarts of water. hope this helped

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1. Classify the triangle according to side length and angle measurement.
mezya [45]

Answer:

1. Scalene right

2. Isosceles acute

3. Parallelogram

3 0
3 years ago
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How many times greater is<br> 3.8 X 10^5 than<br> 1.9 X 10^2<br> 2<br> 20<br> 200<br> 2000
storchak [24]

Answer:

2 * 10^3 = 2000.

Step-by-step explanation:

3.8/1.9 * 10^5/10^2

= 2 * 10^3

6 0
3 years ago
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A simple die is thrown 100 times and the number five appears 14 times. Find the experimental probability of throwing a five, giv
mario62 [17]

Answer:

The experimental probability of throwing a five is 0.087.

Step-by-step explanation:

Given:

Number of trials (n) = 100

Number of times 5 appears (x) = 14

Let the event of occurrence of 5 be success and the probability represented by 'p'. So, all the other numbers occurrence is failure and its probability is represented as 'q'.

Probability of success is given as:

p=\frac{Number\ of\ favorable\ events}{Total\ number\ of\ outcomes}

Favorable event is occurrence of 5. So, its number is 1 as there is only one 5 in the die. Total outcomes are 6 as there are six numbers. So,

p=\frac{1}{6}

Now, probability of failure is given by the formula:

q=1-p=1-\frac{1}{6}=\frac{5}{6}

Now in order to find the experimental probability of 14 successes out of 100 trials, we apply Bernoulli's theorem which is given as:

P(x) = ^nC_xp^xq^{n-x}

Plug in all the given values and find the probability of 14 successes. This gives,

P(x=14)=^{100}C_{14}(\frac{1}{6})^{14}(\frac{5}{6})^{100-14}\\\\P(x=14)=0.087

Therefore, the experimental probability of throwing a five is 0.087.

8 0
4 years ago
factor 3a^5-18a^3+6a^2, I know the answer is 3a^2(a^3-6a+2) but I am so lost on how to get the factor of 3a^2..How in the world
rusak2 [61]

Answer:

\huge\boxed{3a^2(a^3-6a+2)}

Step-by-step explanation:

\sf 3a^5-18a^3+6a^2\\\\HCF = 3a^2\\\\Take \ 3a^2 \ common\\\\= 3a^2(a^3-6a+2)\\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
5 0
3 years ago
Answer if you know
Arlecino [84]
I've attached a plot of one such cross-section (orange) over the region in the x-y plane (blue), including the bounding curves (red). (I've set y=1.25 for this example.)

The length of each cross section (the side lying in the base) has length determined by the horizontal distance x between the y-axis x=0 and the curve y=\sqrt x. In terms of y, this distance is x=y^2. The height of each cross section is twice the value of y, so the area of each rectangular cross section should be 2y^3.

This means the volume would be given by the integral

\displaystyle\int_0^22y^3\,\mathrm dy
8 0
3 years ago
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