Question

What are the zero(s) of the function f(x) = the quantity of 4 x squared minus 36 x, all over x minus 9?

Answer 1

You only need to consider when the numerator is 0
4x^2-36x=x (4x-36)
x=0 only. vertical asymptote at x=9

Answer 2

Answer:

x=0 is the root for the given function

Explanation:

We have been given with the function

$\frac{4x^2-36x}{x-9}$  taking out  4x as the common factor from numerator then we will get

$\frac{4x(x-9)}{(x-9)}$

Now cancel out the common factor from numerator and denominator we will get

4x=0

$\Rightarrow x=0$

Hence, x=0 is the zero of the given function

Zero of the function is solution of the function the point where function gives the value zero