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blagie [28]
2 years ago
6

Write an expression to represent the product of 6 and the square of a number plus 15.

Mathematics
1 answer:
inn [45]2 years ago
8 0

Answer:

6x² + 15

6

Step-by-step explanation:

Let the number be x.

"the square of a number"

x²

"the product of 6 and the square of a number"

6x²

"the product of 6 and the square of a number plus 15"

6x² + 15

The coefficient is the number that multiplies the variable, so it is 6.

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Which values are with in the range of the piecewise defined function?
zepelin [54]

Answer:

y = -6; -3;  0

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The equation is:

f(x)  = 2x+2  , x < -3

f(x) = x, x = -3

f(x) = - x -2 , x > -3

From the graph, we can see that the values are

y = -6; -3;  0

4 0
3 years ago
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HELP ME PLEASE I NEED ANSWERS REALLY FAST I'LL GIVE BRAINLIEST TO THE CORRECT ANSWER SO PLEASE HELP ME!!!!
GuDViN [60]

Answer:

B

Step-by-step explanation:

These lines dont cross CD and are not parrellel which is what skew lines are.

3 0
3 years ago
20 points! Will mark the brainliest!
andrew-mc [135]
\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }

-----------------------------------------------------------------------------------
Write the divide fraction horizontally:
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}

-----------------------------------------------------------------------------------
Factorise the numerators and denominators when possible:
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}

-----------------------------------------------------------------------------------
Convert the divide fraction to multiplication fraction
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}

-----------------------------------------------------------------------------------
Cancel the factors
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= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}

-----------------------------------------------------------------------------------
Combine to single fraction
-----------------------------------------------------------------------------------

= \dfrac{1}{4(x+2)^2}



4 0
3 years ago
Write three different ways for7/10
HACTEHA [7]
The only ways i thought of was 0.7, 0.70, and 0.700 .
7 0
3 years ago
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Choose the function whose graph is given by
Taya2010 [7]

Answer:

The correct option is D.

Step-by-step explanation:

The given graph is the graph of a cosine function, which shifts 1 unit left.

The cosine function is defined as

y=a\cos(bx+c)+d

Where, a is amplitude, b is frequency, c is phase shift and d is vertical shift.

If c>0, then the graph shifts c units left and if c<0, then the graph shifts c units right.

Since the graph show only phase shift and the graph shifts only one unit left, therefore required function is

y=\cos(x+1)

Option D is correct.

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3 years ago
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