First, let me show you some notation.
To show a matrix is an inverse of another matrix, we write

-1 is not an exponent. It just shows that a matrix is an inverse of another matrix.
For a 2x2 matrix, we can get the inverse by first making b and c negatives and swap the positions of a and d.
Then multiply each entry in the matrix by 1 divided by the determinant.
![\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]^{-1} = \frac{1}{ad - bc}\left[\begin{array}{ccc}d&{-b}\\{-c}&a\end{array}\right] = \\ \\ \\ \left[\begin{array}{ccc}d(\frac{1}{ad-bc})&{-b}(\frac{1}{ad-bc}) \\ {-c}(\frac{1}{ad-bc}) &a(\frac{1}{ad-bc}) \end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%5E%7B-1%7D%20%3D%20%0A%20%20%5Cfrac%7B1%7D%7Bad%20-%20bc%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dd%26%7B-b%7D%5C%5C%7B-c%7D%26a%5Cend%7Barray%7D%5Cright%5D%20%3D%20%20%5C%5C%20%20%5C%5C%20%5C%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dd%28%5Cfrac%7B1%7D%7Bad-bc%7D%29%26%7B-b%7D%28%5Cfrac%7B1%7D%7Bad-bc%7D%29%20%5C%5C%20%7B-c%7D%28%5Cfrac%7B1%7D%7Bad-bc%7D%29%20%26a%28%5Cfrac%7B1%7D%7Bad-bc%7D%29%20%5Cend%7Barray%7D%5Cright%5D)
I hope this helped!
Answer:
Without any question we cant signify it !!!!!!????
Step-by-step explanation:
<h3>
Resolution 12 Shaded in.</h3>
Step-by-step explanation: Imagine a triangle with 16 spots and you need to get 75% of it 16 in all is 100 take away 4 spots you get 12 and 12 from 16 is 75 if you do the math
I love these problems, because it's just about reading the question. All you need to do is break it down. What do we know the "sum of" something is? We know that it means addition. What are we adding? "three times a number b and 33". Well, how can we express "three times b"? 3b! Right! Well, we know we're adding that to 33, so you're almost done. Right now you should have 3b+33. And what <em>is</em> 3b+33? at least 33. How can we express "at least"? >=, greater than or equal to, right! Finally, we have our answer. 3b+33>=35.