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3 years ago

All of the following are equivalent except _____.

Mathematics

2 answers:

Mice21 [21]3 years ago

6 0

Answer:

All of the following are equivalent except $(5 - 5)x$

Step-by-step explanation:

A) $-5(x - 1)$

$= -5x +5$

B) $-5x + 5$

C) $5 - 5x$

D) $(5 - 5)x$

$=(0)x$

$=0$

So, A= B = C ≠ D

So, All of the following are equivalent except $(5 - 5)x$

MrRa [10]3 years ago

3 0

This (5 - 5)x is not equivalent

answer is last one (5 - 5)x

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Can someone please explain why this is incorrect? Isn’t (2x+5)(x+1) the same as (x+1)(2x+5)?

Ne4ueva [31]

Answer:

2(2x+5) (x+1) = 2(x+1)(2x+5)

Step-by-step explanation:

4x^2 +14x+10

Factor out the 2

2(2x^2 +7x+5)

2(2x+5) (x+1)

You need to keep the 2 that you factored out

2(2x+5) (x+1) = 2(x+1)(2x+5) by the Commutative Property of Multiplication

4 0

4 years ago

A circle is drawn within a square as shown.

Vinil7 [7]

<h3>Area of shaded region is 21.5 square centimeter</h3>

Solution:

The area of the shaded region is equal to the area of the square minus the area of the circle

Find the area of the square

$Area\ of\ square = a^2$

Where, "a" is the length of each side

From given figure in question,

a = 10 cm

$Area\ of\ square = 10^2\\\\Area\ of\ square = 100\ cm^2$

Find the area of circle

The area of the circle is given as:

$Area\ of\ circle = \pi r^2$

Where, "r" is the radius of circle

Diameter = 10 cm

$r = \frac{diameter}{2}\\\\r = \frac{10}{2}\\\\r = 5$

Thus,

$Area\ of\ circle = 3.14 \times 5^2\\\\Area\ of\ circle = 3.14 \times 25\\\\Area\ of\ circle = 78.5\ cm^2$

Find the area of the shaded region

Area of shaded Region = Area of Square - Area of Circle

Area of shaded Region = 100 - 78.5 = 21.5

Thus area of shaded region is 21.5 square centimeter

7 0

3 years ago

A marketing research firm wishes to compare the prices charged by two supermarket chains—Miller’s and Albert’s. The research fir

AVprozaik [17]

Answer:

a) $F=\frac{s^2_2}{s^2_1}=\frac{1.84^2}{1.4^2}=1.727 \approx 1.73$

b) For this case since we have a two tailed test we have two critical values, and we can find the two values since we need that on each tail the area would be $\alpha/2 =0.025$ , the distribution is the F with 9 df for the numerator and denominator, and we can use the following excel codes to find the critical values:

"=F.INV(0.025,9,9)"

"=F.INV(1-0.025,9,9)"

The two critical values are 0.248 and 4.026, so the rejection zone would be: $F>4.026 \cup F$ since our calculated value is not on the rejection zone we fail to rejec the null hypothesis

Step-by-step explanation:

Data given and notation

$n_1 = 10$ represent the sampe size for the Miller's Stores

$n_2 =10$ represent the sample size for the Albert's stores

$\bar X_1 =121.92$ represent the sample mean for Miller's store

$\bar X_2 =114.81$ represent the sample mean for Albert's store

$s_1 = 1.4$ represent the sample deviation for the Miller's store

$s_2 = 1.84$ represent the sample deviation for the Albert's stores

$s^2_2 = 12.25$ represent the sample variance for the utility stocks

$\alpha=0.05$ represent the significance level provided

Confidence =0.95 or 95%

F test is a statistical test that uses a F Statistic to compare two population variances, with the sample deviations s1 and s2. The F statistic is always positive number since the variance it's always higher than 0. The statistic is given by:

$F=\frac{s^2_2}{s^2_1}$

Solution to the problem

System of hypothesis

We want to test if the variation for th two groups is the same, so the system of hypothesis are:

H0: $\sigma^2_1 = \sigma^2_2$

H1: $\sigma^2_1 \new \sigma^2_2$

a) Calculate the statistic

Now we can calculate the statistic like this:

$F=\frac{s^2_2}{s^2_1}=\frac{1.84^2}{1.4^2}=1.727 \approx 1.73$

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have $n_1 -1 =10-1=9$ and for the denominator we have $n_2 -1 =10-1=9$ and the F statistic have 9 degrees of freedom for the numerator and 9 for the denominator. And the P value is given by:

P value

$p_v =2*P(F_{9,9}>1.727)=0.428$

And we can use the following excel code to find the p value:"=2*(1-F.DIST(1.727,9,9,TRUE))"

b) Critical value

For this case since we have a two tailed test we have two critical values, and we can find the two values since we need that on each tail the area would be $\alpha/2 =0.025$ , the distribution is the F with 9 df for the numerator and denominator, and we can use the following excel codes to find the critical values:

"=F.INV(0.025,9,9)"

"=F.INV(1-0.025,9,9)"

The two critical values are 0.248 and 4.026, so the rejection zone would be: $F>4.026 \cup F$ since our calculated value is not on the rejection zone we fail to rejec the null hypothesis

Since our calcu

Conclusion

Since the $p_v > \alpha$ we have enough evidence to FAIL to reject the null hypothesis. And we can say that we don't have enough evidence to conclude that the two deviations are different at 5% of significance.

8 0

3 years ago

Tim bought a video game console and games for $350. The video game console cost $200. Each game cost $25. How many games did Tim

olasank [31]

Tim bought 6 games
Because 25x6=150 and he spent 200 on the console and he spent 350 total so your answer is $150

3 0

3 years ago

Read 2 more answers

after 20 minutes he is on page 151, after 45 minutes he was on page 181. how many pages had clint read prior to study hall

xeze [42]

127 is the answer bc if you subtract 45-20 that gives you 25 minutes and then in 25 minutes he read 30 pages so you can divide 30÷25 which gives you 1.2 so then you’re going to multiply 20 and 1.2 which gives u 25 and subtract 24 from 151

6 0

3 years ago