The amount of Na₂SO₄ would be 15.09 grams
<h3>Stoichiometric calculation</h3>
From the equation of the reaction:
4NaOH + 2H₂SO₄ --> 2Na₂SO₄ + 4H₂O
Mole ratio of NaOH and Na₂SO₄ = 2:1
Mole of 8.50 grams of NaOH = 8.50/40
= 0.21 mole
Equivalent mole of Na₂SO₄ = 0.21/2
= 0.11 mole
Mass of 0.11 mole Na₂SO₄ = 0.11 x 142.04
= 15.09 grams
More on stoichiometric reactions can be found here: brainly.com/question/8062886


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The given compound has 3 carbon atoms, so in 1 mole of that compound, there will be 3 moles of carbon atoms.
Mass of each mole of carbon atoms = 12 g
For 3 mole carbon atoms, it will be 12 × 3 = 36 grams
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Answer:
Hi the answer should be B or 2
Explanation:
Hope this helps!
The answer is the mass number! (:
PV = nRT
P = (nRT)/V
P = (0.3 mol × 0.08206 atm-l/(mol-K) × (273.15 + 30) K)/(0.5 l)
P = 14.9258934 atm