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kaheart [24]
3 years ago
12

The number of atoms present in 2.5 mole of triatomic gas is equivalent to ​

Chemistry
1 answer:
RUDIKE [14]3 years ago
6 0

Answer: 1.41725 X 10^{24} atoms

Explanation:

One male of any gas containing no. of atoms$=6.023\times10^{23}$

2.5 moles of gas containing no. of atoms$=2.5\times6.023\times10^{23}$$=15.0575\times10^{23}$

The given gas is triatomic gas. Hence

No. of atoms$=3\times15.075\times10^{23}$

$=14.1725\times10^{23}$\\$=1.41725\times10^{24}$

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The Mole #2<br> Avogadro's Number <br> PLEASE HELP ASAP! due tmr will give brainliest!
Elis [28]

The solution is here,

given mass of copper wire(m)=25 g

no. of moles in given mass of Cu=0.393

a) no. of atoms= no. of moles×avogardo's number

=0.393×6.023×10^23=2.36 ×10^23 atoms

b) 25 g of Cu wire has 0.393 moles

so 200 g of Cu wire has 0.393/25 × 200=3.144 mol.

no. of atoms= 3.144×2.023×10^23=1.89×10^24 atoms.

c) 25 g of Cu wire has 2.36×10^23 atoms

so 5 g of Cu wire has (2.36×10^23)/25 × 5

=4.72×10^22 atoms

( b can also be solve like c)

7 0
3 years ago
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Triss [41]

Answer: average speed

Explanation: describes speed of motion when speed is changing.

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3 years ago
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klemol [59]
They are trying to answer a question
3 0
4 years ago
An unknown volume of gas has a pressure of 0.50 atm and temperature of 325 K. If the pressure is raised to 1.2 atm and the tempe
Grace [21]
You can solve this by using the equation (P1V1/T1) = (P2V2/T2). Plug in 0.50 atm for P1, leave V1 as the unknown, and plug in 325 K as T1. Then substitute 1.2 atm for P2, 48 L for V2, and 320 K for T2. Solve for V1, which is 117L, but since you round using two sig figs, your answer is C, 120 L. Hope this helps!
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Explanation:

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More strong interactions present in the atoms of a compound more heat is required to break it. Hence, greater will be its boiling point.

As the boiling point of oxygen is 90 K so, at a temperature greater than it will change the state of oxygen from liquid to gas.

Similarly, the boiling point of nitrogen is 77 K so, at a temperature 95 K the state of liquid will also change from liquid to gas.

6 0
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