Question

The number of atoms present in 2.5 mole of triatomic gas is equivalent to ​

Answer 1

Answer: 1.41725 X 10^{24} atoms

Explanation:

One male of any gas containing no. of atoms$=6.023\times10^{23}$

2.5 moles of gas containing no. of atoms$=2.5\times6.023\times10^{23} =15.0575\times10^{23}$

The given gas is triatomic gas. Hence

No. of atoms$=3\times15.075\times10^{23}$

$=14.1725\times10^{23} \\ =1.41725\times10^{24}$