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vlabodo [156]
3 years ago
14

Which function is nonlinear? Y=4x+9 y=7/x-6 y=x-6/7 15 points

Mathematics
1 answer:
AleksAgata [21]3 years ago
5 0

Answer:

The answer is y = 7/x -6.

Step-by-step explanation:

A linear function is one where x and y are both to the first power.  Using this knowledge, let's look at the options that we are given.

y = 4x + 9

In the above equation, both x and y are raised to the first power, so we know that this equation is linear.

y = 7/x - 6

In the above equation, y is raised to the first power, but x is not.  Since x is in the denominator of a fraction, it actually has a power of -1, which makes this equation nonlinear.

y = x - 6/7

In the above equation, both x and y are raised to the first power, making the equation linear.

Therefore, the correct choice is y =7/x - 6.

Hope this helps!

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What is equation of a line that is parallel to y = -6x – 1 and passes through the point (1,4)
Akimi4 [234]

Answer:

y = -6x + 10

Step-by-step explanation:

Parallel lines share the same slope.  Given y = -6x – 1, we know that the equation of this new line has the form y = -6x – C.  The coordinates of the point (1, 4) determine the value of C:

(4) = -6(1) – C, or:

4 = -6 - C

Then C = -10, and the desired equation is

y = -6x – (-10), or

y = -6x + 10

5 0
3 years ago
The vertices of triangle RST are R (-7, 5), S(17, 5), T(5, 0). What is the perimeter of triangle RST?
MaRussiya [10]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}

~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill

3 0
1 year ago
Yo can yall help me need help to pass
kari74 [83]

Answer:

(3, 5)

Step-by-step explanation:

Point (3, -5) is 5 units below the x-axis.

After it is reflected, it will be 5 units above the x-axis.

Answer: (3, 5)

3 0
3 years ago
Read 2 more answers
Snoopy the dog is on a 11-ft long chain that is attached to the corner of a garage (see the picture below). If the chain does no
seropon [69]
11*2 = 22 (calculating the diameter)

Using πD for the area:
π * 22 = 22π

Getting 3/4 of the area because the dog can not move past the corners of the garage;

22π * 3/4 = 16.5π

Getting the answer in feet^2:
16.5 * 3.14 = 51.84 feet^2

Hope this helps! :)
5 0
3 years ago
May I have help to figure out how to do this? It is confusing! :(
RSB [31]

Answer:

it should be 80%

Step-by-step explanation:

I hope this helps

3 0
3 years ago
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