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beks73 [17]
2 years ago
10

May I have help to figure out how to do this? It is confusing! :(

Mathematics
1 answer:
RSB [31]2 years ago
3 0

Answer:

it should be 80%

Step-by-step explanation:

I hope this helps

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PLS HELP THIS IS LAST OF MY POINTS AND RUNNING OUT OF TIME. ANSWER ONLY IF U KNOW MATH.
ipn [44]

Answer:

using y=mx +c

c=0

m=y2-y2/x2-x1

m=16-0/2-0

m=8

y=8x+0

y=8x

hope that helped

if yes give me brainliest and if no draw my attention by hitting the comment section

7 0
2 years ago
Read 2 more answers
A jogger can jog 3 miles in 15 minutes and 18 miles in 1 1/2 hours. If the number of miles and the time are in a proportional li
Anastaziya [24]

Answer: He jogs 12 miles per hour

Step-by-step explanation: Every 15 minutes he jogs 3 miles, there are 60 minutes in an hour, 60/15 = 4, 4 x 3 = 12

8 0
3 years ago
Write an equation in slope-intercept form (y = mx + b).
Wewaii [24]

Answer:

y = 2/7x + 7

Step-by-step explanation:

We start off by putting the original equation into slope-intercept form. Subtract 7x from both sides, then divide both sides by -2. Your new equation should be y = -7/2x - 8. It's important to know that when two lines are perpendicular, their slopes (m) are opposite reciprocals of each other.  So -7/2 becomes 2/7. The first part of your final equation is y = 2/7x + b.

Next, we need to find the y intercept (b). You need to plug the x and y values from the given coordinate point (-7,5) into your final equation. You should end up with: 5 = 2/7(-7) + b. Then, solve for b.

5 = -14/7 + b

5 = -2 + b

7 = b

Finally, plug the b value into your final equation and you will have your answer.

4 0
3 years ago
How do i find sin^-1(cos(pi)) and answer in radians in terms of pi
vaieri [72.5K]
We have to find sin^(-1) ( cos π ).
cos π = cos 180° = - 1
sin^(-1) ( - 1 ) = 270° = 3 π / 2
Answer:
sin ^
sin^(-1)( cos π ) = 3 π / 2 
7 0
3 years ago
Can someone help me match these up? i know the given is number one I need help with the rest.
EleoNora [17]
C-1\\E-2\\B-3\\D-4\\A-5
6 0
3 years ago
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