This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...
h=-2t^2+9t+11
A)
dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached
dh/dt=0 only when 4t=9, t=2.25 seconds
h(2.25)=21.125 ft (21 1/8 ft)
B)
As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.
C)
The squirrel reaches the ground when h=0...
0=-2t^2+9t+11
-2t^2-2t+11t+11=0
-2t(t+1)+11(t+1)=0
(-2t+11)(t+1)=0, since t>0 for this problem...
-2t+11=0
-2t=-11
t=5.5 seconds.
Answer:
Try D) rotation 180 degrees about the origin.
Step-by-step explanation:
When you look at it, it appears to move 180 degrees about that origin.
Hope this helps! Let me know!
Answer:
Explanation:
<u>1. Calculate the monthly interest owed during year 1</u>
<u />
- <em>Interest for first year: 8%</em>
- The monthly rate is the yearly rate divided by 12: 8% / 12 = 0.08/12
- The monthly interest owed is the monthly rate times the balance: (0.08/12)×$1,800 = $12.00
<u>2. Calculate the monthly interest owed during year 2</u>
<u />
- <em>Interest for second year: 23%</em>
- The montly rate is the yearly rate divided by 12: 23% / 12 = 0.23/12
- The monthly interest owed is the monthly rate times the balance: (0.23/12)×$1,800 = $34.50
<u>3. Calculate the difference</u>
- Difference in the monthly interest owed during year 1 and year 2 = $34.50 - $12.00 = $22.50
Hence, the answer is the option c) $22.50
Answer:
sorry for points
Step-by-step explanation:
Its A,have a nice day! :))))))
