I assume you're asked to solve
4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0
Factor the left side:
(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0
Then either
4 cos(<em>x</em>) - 3 = 0 <u>or</u> cos(<em>x</em>) - 1 = 0
cos(<em>x</em>) = 3/4 <u>or</u> cos(<em>x</em>) = 1
From the first case, we get
<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em> <u>or</u> <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>
and from the second,
<em>x</em> = <em>nπ</em>
where <em>n</em> is any integer.
If 4/5 of the total is 48, the total can be found by dividing it by 4 and multiplying it by 5:
48/4 = 12
12*5 = 60.
Answer:
144
Step-by-step explanation:
Because the horizontal lines are parallel <7 is the same as <4. Because <1 and <7 are on a straight line they must add up to 180. <7 + 36 = 180 so <7=144 so <1 is also 144.
Answer:
D. Both distributions are skewed left, so the interquartile range is the best measure to compare variability.
Step-by-step explanation:
Plotting the data roughly shows that the data is skewed to the left. In other words, data is skewed negatively and that the long tail will be on the negative side of the peak.
In such a scenario, interquartile range is normally the best measure to compare variations of data.
Therefore, the last option is the best for the data provided.
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