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juin [17]
3 years ago
14

Kim drives 156 miles from Rotherham to London.

Mathematics
2 answers:
9966 [12]3 years ago
6 0

Answer:

No, she will not arrive  London before 10:00 am.

Step-by-step explanation:

It is given that:

Kim drives 156 miles from Rotherham to London.

She drives at an average speed of 60 miles per hour.

i.e. in one hour she drives 60 miles.

Hence she covers 1 mile in 1/60 hours.

Now she has to travel 156 miles.

i.e. it takes her:

156/60 hours=2.6 hours.

i.e. it takes her 2 hours and 36 minutes to reach from Rotherham to London.

(

since 0.6 hours=36 minutes.

As 1 hour= 60 minutes.

so, 0.6 hours=0.6×60=36 minutes ).

Hence, if she start from Rotherham at 7:30 am.

Then she will reach London at:

7:30+2.6=10:06 am.

Hence, she will reach London after 10 am.

masya89 [10]3 years ago
4 0
No. See, you can take 60 out of 156 twice and you are left with 36. This means the drive would take about 2 hours and 36 minuets. 7+2=9 30+36=66 so then you add an our the time and you get that she would arrive a few minuets afterwards. (I'm sorry if I didn't explain this very well)
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Element X is a radioactive isotope such that its mass decreases by 26% every day. If an experiment starts out with 810 grams of
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Answer:

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

The function to represent the mass of the sample after t days is A(t) = 810(0.74)^t

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the amount of a substance is given by:

A(t) = A(0)(1-r)^t

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Hourly rate of change:

Decreases 26% by day. A day has 24 hours. This means that A(24) = (1-0.26)A(0) = 0.74A(0); We use this to find r.

A(t) = A(0)(1-r)^t

0.74A(0) = A(0)(1-r)^{24}

(1-r)^{24} = 0.74

\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}

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1 - r = 0.9875

r = 1 - 0.9875 = 0.0125

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

Starts out with 810 grams of Element X

This means that A(0) = 810

Element X is a radioactive isotope such that its mass decreases by 26% every day.

This means that we use, for this equation, r = 0.26.

The equation is:

A(t) = A(0)(1-r)^t

A(t) = 810(1 - 0.26)^t

A(t) = 810(0.74)^t

The function to represent the mass of the sample after t days is A(t) = 810(0.74)^t

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3 years ago
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