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3 years ago

To compare 5 in tens place to 5 in the hundreds place in the number 5,555

Mathematics

1 answer:

galina1969 [7]3 years ago

6 0

Answer:

I'm not sure what you are asking for?

Step-by-step explanation:

The 5 in the tens place = 50, and the 5 in the hundreds place = 500.

To compare them (Are you asking me for the difference between them???), then, 500 - 50 = 450.

But, again, I'm not sure what you want.

You might be interested in

Indicate which formula you would use to solve for the missing side B and then write your answer correct to two decimal places.Wr

agasfer [191]

Answer:

The measure of the angle $b$ is approximately 44.040°.

Step-by-step explanation:

We need to apply Law of the Sine to determine the value of angle $b$ , since the length of the side opposite to this side and another side length and its opposite angle are known. That is:

$\frac{3.6}{\sin b} = \frac{5.1}{\sin 100^{\circ}}$

$\sin b = \frac{3.6}{5.1}\times \sin 100^{\circ}$

$b = \sin^{-1}\left(\frac{3.6}{5.1}\times \sin 100^{\circ} \right)$

$b \approx 44.040^{\circ}$

The measure of the angle $b$ is approximately 44.040°.

4 0

2 years ago

A surveyor sights the far bank of a river at an angle of 110° to the near bank. She then moves 75 feet upriver and sights the sa

Leya [2.2K]

Answer:

Correct answer is 54.82 ft.

Step-by-step explanation:

First of all, let us label the diagram and do the construction as per the attached answer image.

Let us consider $\triangle ABC$ :

$\angle B = 90^\circ\\\angle ACB = 180-110 = 70^\circ$

Let side AB = d ft and let side BC = x ft

We need to find AB to find the shortest distance across the river.

Using trigonometric identity of tangent:

$tan\theta = \dfrac{Perpendicular}{Base}$

$tan 70 = \dfrac{d}{x}\\\Rightarrow x = \dfrac{d}{tan70} = 0.36d ..... (1)$

Now, let us have a look at another right angled triangle ABD:

Let us consider $\triangle ABC$ :

$\angle B = 90^\circ\\\angle ADB = 180-150 = 30^\circ$

side AB = d ft and side BD = x+75 ft

Using trigonometric identity of tangent:

$tan\theta = \dfrac{Perpendicular}{Base}$

$tan 30 = \dfrac{d}{x+75}\\\text{Using equation (1)}:\\0.577 = \dfrac{d}{0.36d+75}\\\Rightarrow 0.207d + 43.27 = d\\\Rightarrow 0.793d = 43.27\\\Rightarrow d \approx 54.82\ ft$