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3 years ago

What is 1/4(9y-3)+1/8(6y+9) simplified?

Mathematics

2 answers:

dusya [7]3 years ago

8 0

Answer:

3y+3\8

Step-by-step explanation:

frosja888 [35]3 years ago

6 0

Answer:

Timdec is right. If you distribute the values to each other and then add them, you get his answer

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If x = 3 is a zero of the polynomial function f(x) = 2x3 + x2 − 25x + 12, which of the following is another zero of f(x)?a. x =

FromTheMoon [43]

Answer:

b) $x=-4$ is another zero of the polynomial

Step-by-step explanation:

Since you are given a set of options to choose from, a very simple way to find the zero of the polynomial is by simply plugging each value from the options and seeing which of them gives the answer 0.

$f(x) = 2x^3+x^2-25x+12\\$

Using all the options:

$a)\,f(-3) = 2(-3)^3+(-3)^2-25(-3)+12\\f(-3) = 42\\\\b)\,f(4) = 2(4)^3+(4)^2-25(4)+12\\f(4) = 56\\\\c)\,f(-4) = 2(-4)^3+(-4)^2-25(-4)+12\\f(-4) = 0\\\\d)\,f(12) = 2(12)^3+(12)^2-25(12)+12\\f(12) = 3312$

Now we know that at x = -4 the value of the polynomial f(x) is 0. hence

b) $x=-4$ is another zero of the polynomial

7 0

3 years ago

Savannah buys a $40 gift card to her favorite smoothie shop. Each smoothie costs $4. She wants to have at least $10 left on her

Anton [14]

Answer:

3 smothies

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which statement is true about this question -4(2p+5)+8p=-11

aleksandrvk [35]

The answer to this problem is “C “

6 0

3 years ago

161 divided by 4 , need a pic with the answer....

ludmilkaskok [199]

Answer:

40.25 if my math is right

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini

svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

$x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2$

The augmented matrix is

$\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]$

The reduction of this matrix to row-echelon form is outlined below.

$R_2\rightarrow R_2-R_1$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]$

$R_3\rightarrow R_3-2R_1$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]$

$R_3\rightarrow R_3-R_2$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]$

The last row determines, if there are solutions or not. To be consistent, we must have k such that

$k^2-k-2=0$

$\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2$

Case k = −1:

$\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]$

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

$\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]$

This gives the infinite many solution.

5 0

3 years ago