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3 years ago

A drawing has a scale 1/4 in: 12ft. How long is 8ft?

1 answer:

4 0

If you use a proportion, you'll get:

$\frac{0.25}{12} = \frac{x}{8}$

Then, you use cross products:

$12x=0.25(8) \\ 12x=2$

Then, you algebraically solve x:

$12x=2 \\ \frac{12x}{12} = \frac{2}{12} \\ x= \frac{5}{3}$

The answer is 5/3 inches , or 1 5/13 inches, or 1.6 repeating.

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12-(3-9) 3*3 help please

Verdich [7]

Step-by-step explanation:

42 is your answer according to bodmas

8 0

2 years ago

Billy-Bob has a piggy-bank filled with nickels and quarters totaling $11.90.

Lunna [17]

Answer:

x = 33

y = 41

Step-by-step explanation:

GIven

x: number of nickels

y: number of quarters

A nickel = $0.05

A quarter = $0.25

then we have the system of equations

0.05*x + 0.25*y = 11.90

x + y = 74

Which can be solved applying any of known methods. Then, the solution is

x = 33

y = 41

hope this was helpful.

4 0

2 years ago

Consider the function f(x)=2|x|-3. What is f(-3)?

olganol [36]

f(-3)= $2|-3|-3=6-3=3\\f(-3)=3$

Hope I helped and have a great day!

P.S. brainliest would really help im one away from virtuoso

8 0

3 years ago

In what quadrant will θ terminate, if sin θ is positive and sec θ is negative?

kow [346]

Sin x is possitive in two quadrants :

quadrant I and quadrant II

in quadrant I, cos x is positive

in quadrant II , cos x is negative

so i think the answer is : quadrant II

hope this helps

5 0

2 years ago

The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen

e-lub [12.9K]

Answer with Step-by-step explanation:

Since the given event is binary we can use Bernoulli's probability to sove the problem

Thus for an event 'E' with probability of success 'p' the probability that the event occurs 'r' times in 'n' trails is given by

$P(E)=\frac{n!}{(n-r)!\cdot r!}\cdot p^{r}\cdot (1-p)^{n-r}$

Part a)

For part a n = 11 , r =9, p = 0.75

Applying values we get

$P(E)=\frac{11!}{(11-9)!\cdot 9!}\cdot (0.75)^{9}\cdot (1-0.75)^{11-9}\\\\\therefore P(E)=0.2581$

Part b)

For part b n = 20 , r = 16 , p=0.75

Applying values we get

$P(E)=\frac{20!}{(20-16)!\cdot 16!}\cdot (0.75)^{16}\cdot (1-0.75)^{20-16}\\\\\therefore P(E)=0.1896$

3 0

3 years ago